Question: Evaluate : 1-cos 6xdx, where x (0, π6)


A ) 23cos x + C
B ) - 23cos 3x + C
C ) 23cos 3x + C
D ) 22cos x + C

Steps to derive

1 1-cos 6xdx=2sin23xdx
 [Use 1 - cos 2x = 2sin2x.]

2 = 2sin 3xdx
 [3x (0, π2).]

3 = (2)sin 3xdx

4 = (23)(-cos 3x) + C

5 = - 23cos 3x + C



Hence the right answer is Option B

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