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Question: Factor the trinomial.
3y2 - 10y - 8


A ) (y - 2)(3y + 4)
B ) (y - 4)(3y + 2)
C ) (y + 3)(2y + 2)
D ) (y - 1)(3y - 8)

Steps to derive

1 3y2 - 10y - 8
 [Given trinomial.]

2 a = 3, b = - 10, c = - 8
 [Compare with ax² + bx + c.]

3 Find two numbers whose product is 3 and another two numbers whose product is - 8.
    Factors of 3       Factors of - 8
         1, 3           - 1, 8; - 2, 4 and - 4, 2

4 Use FOIL method to check the middle term in the trial factors.
    Trial factors           Middle term
    (y - 1)(3y + 8)      8y - 3y = 5y
    (y - 2)(3y + 4)     4y - 6y = - 2y
    (y - 4)(3y + 2)     2y - 12y = - 10y

5 So, 3y2 - 10y - 8 = (y - 4)(3y + 2).



Hence the right answer is Option B

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