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Grade 19 Algebra I
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Polynomials -Factorization of Trinomials (ax² + bx + c Form)
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Question: Factor the trinomial.
3
y
2
- 10
y
- 8
A ) (
y
- 2)(3
y
+ 4)
B ) (
y
- 4)(3
y
+ 2)
C ) (
y
+ 3)(2
y
+ 2)
D ) (
y
- 1)(3
y
- 8)
Steps to derive
1
3
y
2
- 10
y
- 8
[Given trinomial.]
2
a
= 3,
b
= - 10,
c
= - 8
[Compare with
ax
² +
bx
+
c
.]
3
Find two numbers whose product is 3 and another two numbers whose product is - 8.
Factors of 3 Factors of - 8
1, 3 - 1, 8; - 2, 4 and - 4, 2
4
Use FOIL method to check the middle term in the trial factors.
Trial factors Middle term
(
y
- 1)(3
y
+ 8) 8
y
- 3
y
= 5
y
(
y
- 2)(3
y
+ 4) 4
y
- 6
y
= - 2
y
(
y
- 4)(3
y
+ 2) 2
y
- 12
y
= - 10
y
5
So, 3
y
2
- 10
y
- 8 = (
y
- 4)(3
y
+ 2).
Hence the right answer is Option B
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