Question: Find the area of an equilateral triangle whose height is 10 in.
A ) (1003) in2
B ) (203) in2
C ) (2003) in2
D ) (103) in2
Steps to derive
1 Let a be length of the side of the equilateral triangle whose height is 10 in. as shown.
2 sin 60° = ha=10a
[Use the sine ratio.]
3 32=10a
4 a = 203
[Cross - product property.]
5 So, area of triangle = (12) ×side length × side length × Sine of included angle.
[Area of triangle given SAS.]
6 = (12)(203)(203) sin 60° = (1003) in2.
Hence the right answer is Option A
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