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Grade 23 Calculus
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Trigonometric and Inverse Trigonometric Functions -Derivatives of Trigonometric Functions
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Question: Find the derivative of cosec
x
.
A ) cosec
x
cot
x
B ) -cosec
x
cot
x
C ) -sec
x
tan
x
D ) sec
x
tan
x
Steps to derive
1
Derivative of cosec
x
=
d
d
x
(
cos
e
c
x
)
2
=
lim
h
→
0
cos
e
c
(
x
+
h
)
-
cos
e
c
x
h
[Use the definition of derivative of function.]
3
=
lim
h
→
0
1
sin
(
x
+
h
)
-
1
sin
x
h
4
=
lim
h
→
0
sin
x
-
sin
(
x
+
h
)
h
sin
(
x
+
h
)
sin
x
5
=
lim
h
→
0
2
cos
(
x
+
x
+
h
2
)
sin
(
x
-
x
-
h
2
)
h
sin
(
x
+
h
)
sin
x
[Use sin A - sin B = 2cos
A
+
B
2
sin
A
-
B
2
.]
6
= -2
lim
h
→
0
cos
(
x
+
h
2
)
sin
(
h
2
)
h
sin
(
x
+
h
)
sin
x
7
= -2(
lim
h
→
0
cos
(
x
+
h
2
)
sin
(
x
+
h
)
sin
x
)
(
lim
h
→
0
sin
(
h
2
)
h
)
[Use the product law of limits.]
8
= -2(
cos
(
x
+
0
)
sin
(
x
+
0
)
sin
x
)
(
1
2
)
[Use
lim
θ
→
0
sin
k
θ
θ
=
k
.]
9
= -(
cos
x
sin
x
sin
x
)
=
-
cos
e
c
x
cot
x
Hence the right answer is Option B
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