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Grade 21 Algebra II
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Trigonometric Identities and Equations -Double Angles and Half Angles
Question: Find the exact value of
tan 150°
using half-angle formula.
A ) -
3
3
B )
3
3
C )
3
D ) -
3
Steps to derive
1
tan 150° =
1 - cos 300
o
sin 300
o
[Use tan
x
2
=
1
-
cos
x
sin
x
, 150° =
300
o
2
.]
2
=
1
-
1
2
-
3
2
[Using cos 300° =
1
2
; sin 300° = -
3
2
.]
3
=
1
2
×
-
2
3
= -
1
3
= -
3
3
Hence the right answer is Option A
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