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Question: Identify the graph that represents the equation 4x² + 8y² = 32.



A ) Graph 4
B ) Graph 3
C ) Graph 1
D ) Graph 2

Steps to derive

1 4x2 + 8y2 = 32
 [Given.]

2 x28 + y24 = 1
 [Divide both sides of the equation by 32.]

3 The standard form of the equation of ellipse is (x - h)2a2 + (y - k)2b 2 = 1.
 [(x, y) are the coordinates of a point on the ellipse and (h, k) is the center of the ellipse.]

4 Compare the given equation with the standard form of the equation of ellipse.

5 The center of the ellipse is at (0, 0).

6 a2 = 8

7 a = 22
 [Take square root on both sides of the equation.]

8 b2 = 4

9 b = 2
 [Take square root on both sides of the equation.]

10 Length of the major axis = 2a
= 2(22) = 42 units

11 Length of the minor axis = 2b
= 2(2) = 4 units

12 c2 = a2 - b2
 [Relation between a, b, and c.]

13 c2 = 8 - 4 = 4

14 c = 2
 [Take square root on both sides of the equation.]

15 So, the foci of the ellipse are (2, 0) and (- 2, 0).
 [The foci of the ellipse are (c, 0) and (- c, 0).]

16 From the given graphs, we can observe that the ellipse in Graph 4 have center at the origin, foci as (2, 0) and (- 2, 0), length of the major axis as 42 units and minor axis as 4 units, x-intercepts as (± 22, 0), and y-intercepts as (± 2, 0).

17 Therefore, Graph 4 represents the given equation of the ellipse.



Hence the right answer is Option A

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