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Question: If the points (- 1, - 1), (- 1, 2), (3, 2) are joined by line segments to create the triangular region, then which system of linear inequalities defines the triangular region. A ) x ≥1, y ≥ 2, and 4y ≥ 3x - 1 B ) x ≥ - 1, y ≤ 2 and 4y ≥ 3x - 1 C ) x ≥1, y ≤ 2 and 4y ≥ 3x - 1 D ) x ≤ - 1, y ≥ 2 and 4y ≥ 3x - 1 Steps to derive 1 Plot the points (- 1, - 1), (- 1, 2), (3, 2) and join them by line segments to create the triangular region.3 Equation of line (1) crosses the x -axis at (- 1, 0) and parallel to y -axis is x = - 1.4 Since the shaded region is to the right of the solid boundary line (1), the inequality is x ≥ - 1.5 Equation of line (2) crosses the y -axis at (0, 2) and parallel to x -axis is y = 2.6 Since the shaded region is below the solid boundary line (2) the inequality is y ≤ 2.7 Line (3) passes through the points (- 1, - 1) and (3, 2).8 m = y 2 - y 1 x 2 - x 1 = 2 - ( - 1 ) 3 - ( - 1 ) = 3 4 [Substitute co-ordinates into slope formula and simplify.]9 y = m x + b [Write slope-intercept form.]10 - 1 = 3 4 (- 1) + b [Replace x with - 1, y with - 1, and m with 3 4 .]11 - 1 + 3 4 = b [Simplify.]12 - 1 4 = b [Solve for b .]13 The equation of line (3) is y = 3 4 x - 1 4 14 4y = 3x - 1 [Simplify.]15 Since the shaded region is above the solid boundary line (3), the inequality is 4y ≥ 3x - 1.16 The system of inequalities that describes the triangular region is x ≥ - 1, y ≤ 2 and 4y ≥ 3x - 1.Hence the right answer is Option B Click Here To Go Back Few Other Questions - Evaluate: limx→1 [1-x2+x3- . . . . . -x641+x2+x3+.. 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