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Question: If the points (- 1, - 1), (- 1, 2), (3, 2) are joined by line segments to create the triangular region, then which system of linear inequalities defines the triangular region.


A ) x ≥1, y ≥ 2, and 4y ≥ 3x - 1
B ) x ≥ - 1, y ≤ 2 and 4y ≥ 3x - 1
C ) x ≥1, y ≤ 2 and 4y ≥ 3x - 1
D ) x ≤ - 1, y ≥ 2 and 4y ≥ 3x - 1

Steps to derive

1 Plot the points (- 1, - 1), (- 1, 2), (3, 2) and join them by line segments to create the triangular region.



3 Equation of line (1) crosses the x-axis at (- 1, 0) and parallel to y-axis is x = - 1.

4 Since the shaded region is to the right of the solid boundary line (1), the inequality is x ≥ - 1.

5 Equation of line (2) crosses the y-axis at (0, 2) and parallel to x-axis is y = 2.

6 Since the shaded region is below the solid boundary line (2) the inequality is y ≤ 2.

7 Line (3) passes through the points (- 1, - 1) and (3, 2).

8 m = y2-y1x2-x1 = 2-(-1)3-(-1) = 34
 [Substitute co-ordinates into slope formula and simplify.]

9 y = mx + b
 [Write slope-intercept form.]

10 - 1 = 34(- 1) + b
 [Replace x with - 1, y with - 1, and m with 34.]

11 - 1 + 34 = b
 [Simplify.]

12 - 14 = b
 [Solve for b.]

13 The equation of line (3) is y = 34x - 14

14 4y = 3x - 1
 [Simplify.]

15 Since the shaded region is above the solid boundary line (3), the inequality is 4y≥ 3x - 1.

16 The system of inequalities that describes the triangular region is x ≥ - 1, y ≤ 2 and 4y ≥ 3x - 1.



Hence the right answer is Option B

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