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Question: Isosceles triangles ABC and PQR are congruent. Angle bisectors of ABC and ACB meet at D. Angle bisectors of PQR and PRQ meet at M. With what postulate of congruency of triangles can you prove that BD = QM?



A ) AAA postulate
B ) SAS postulate
C ) ASA postulate
D ) AAS postulate

Steps to derive

1 Since ΔABC ΔPQR, AB PQ, AC PR, BC QR.

2 ABD + DBC = PQM + MQR
 [Since BD and QM are the angular bisectors.]

3  DBC MQR

4 Similarly, ACB PRQ

5 ACD + DCB PRM + MRQ

6 DCB MRQ

7 BC QR
 [Since ΔABC ΔPQR.]

8 If two angles and included side of one triangle are congruent to two angles and the included side of another triangle, then the two triangles are congruent.
 [ASA postulate.]

9 Hence ΔBDC ΔQMR
 [ASA postulate.]

10 Hence BD = QM.

11 So, ASA postulate can be applied to prove that BD = QM.



Hence the right answer is Option C

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