Question: Plant scientists developed different varieties of corns that have a rich content of lysine which is a nutritious animal feed. A group of chicks were given this food to test the quality. Weight gains (in grams) of these chicks after 21 days are as recorded: 380, 321, 366, 356, 349, 337, 399, 384, 410, 329, 350, 340, 324, 396, 412, 420, 382, 318, 344, 438. By constructing a frequency distribution table for 7 classes, find the class interval in which the weight increase is maximum. Steps to derive 1 Range of the data = higher value - lower value = 438 - 318 = 1202 Width = R a n g e n u m b e r o f c l a s s e s 120 7 ≈ 3 Constuct the class limits (weight gains) with width 18, so that the least and highest values has been included.
4 The class limits, boundaries, tally marks and the frequency for each class (number of tally marks) are shown in the table.
6 The class interval in which the weight increase maximum is 336 - 353.Hence the right answer is Option D Click Here To Go Back How many terms of the geometric sequence 6, 62, 63... are needed to give the sum 1554?.. Evaluate ∑n = 41048n ... In a geometric series a1 = 216 and 4th term is 125. Find the sum of the first 4 terms... Find the sum of first 10 terms, S10 in the geometric series. 1 + 0.8 + 0.64 + 0.512 + ...... Find the sum of first n terms of the geometric series. c3, c6, c9, ..... Evaluate ∑k = 118(1 + 2k)... Find the common ratio of the geometric series whose sum of first 34 terms, S34 = 634 .. If an = 6(3)n in a geometric sequence, then find S6... Find the sum of 34 terms, S34 in the geometric series. (xy) + (x4y) + (x7y) + ..... Find the sum of the first 6 terms of the geometric series. 2, 14, 72, 714, ...... .. The fifth term of a geometric series is 6561 and the second term is 4608. What is the sum .. 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