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Grade 21 Algebra II
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Systems of Equations and Inequalities -Solving Linear Systems (Substitution Method)
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Question: Solve the system by substitution:
4
x
- 2
y
= 6
- 10
x
+ 5
y
= - 15
A ) (2, 0)
B ) (2, 3)
C ) Infinite solutions
D ) No solution
Steps to derive
1
4
x
- 2
y
= 6
[First equation.]
2
- 2
y
= 6 - 4
x
[Subtract 4
x
from the two sides of the equation.]
3
y
= - 3 + 2
x
[Divide through out by - 2 from each side.]
4
- 10
x
+ 5
y
= - 15
[Second equation.]
5
- 10
x
+ 5(- 3 + 2
x
) = - 15
[Substitute the values.]
6
- 10
x
- 15 + 10
x
= - 15
7
- 15 = - 15
8
The above equation is always true, the number of solutions is infinite.
9
The solution is { (
x
,
y
): 4
x
- 2
y
= 6 }.
Hence the right answer is Option C
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