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Question: The blood urea nitrogen (in milligrams per deciliter - mg/dl) count of 20 randomly selected patients is shown in the frequency distribution table. Blood urea nitrogen Frequency 11 - 13 3 13 - 15 4 15 - 17 3 17 - 19 5 19 - 21 5
Steps to derive 1 The midpoint of each class (blood urea nitrogen) and the product with the frequency is as shown in the table.2 Variance of the sample, s 2 = Σ f X 2 - [ ( Σ f X ) 2 n ] n - 1 n ∑ f 3 = 5 6 0 4 - [ ( 3 3 0 ) 2 2 0 ] 1 9 4 = 5 6 0 4 - 5 4 4 5 1 9 5 = 1 5 9 1 9 6 So, the sample variance is 8.4.7 Sample standard deviation, s s a m p l e v a r i a n c e 8 . 4 8 So, the sample standard deviation is 2.9.9 The blood urea nitrogen count of 20 patients has a sample variance of 8.4 and a sample standard deviation of 2.9.Hence the right answer is Option C Click Here To Go Back Which of the following is an arithmetic sequence?I. 6, 10, 14, 18, ...II. 8, 11, 14,.. Identify the common difference of the arithmetic sequence. 10, 7, 4, 1, - 2, ..... The nth term of the arithmetic sequence 6, 12, 18, 24, ... is ______... Find the common difference of the arithmetic sequence and identify the next two terms.34, .. A bank pays 3% interest compounded yearly on a deposit of $600. 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