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Question: The data represents the percentage of children suffering from vascular diseases in 8 selected areas of 2 different countries. Find the mean, median, mode and midrange for country 1 and country 2. Steps to derive 1 Mean percentage of children suffering from vascular diseases in country 1 is X ‾ ∑X n 2 = 5 + 6 . 8 3 + 2 . 9 + 1 4 . 5 6 + 9 . 0 1 + 1 . 8 9 + 1 2 . 9 1 + 1 3 8 3 = 6 6 . 1 8 4 So, the mean percentage of children suffering from vascular diseases in country 1 = 8.263%.5 Arrange the data values of country 1 in order: 1.89%, 2.9%, 5%, 6.83%, 9.01%, 12.91%, 13%, 14.56%.6 The median percentage is MD = 6 . 8 3 + 9 . 0 1 2 7 There is no mode since each value occurs only once.8 Midrange, MR = 1 . 8 9 + 1 4 . 5 6 2 l o w e s t v a l u e + h i g h e s t v a l u e 2 9 Mean percentage of children suffering from vascular diseases in country 2 is X ‾ ∑X n 10 = 2 . 9 + 1 . 0 2 + 1 2 . 9 1 + 1 3 . 0 2 + 4 . 8 6 + 2 . 9 + 0 . 0 9 + 1 1 . 2 3 8 11 = 48.93 8 12 So, the mean percentage of children suffering from vascular diseases in country 2 = 6.116%.13 Arrange the data values of country 2 in order: 0.09%, 1.02%, 2.9%, 2.9%, 4.86%, 11.23%, 12.91%, 13.02%.14 The median percentage is MD = 2 . 9 + 4 . 8 6 2 15 The mode is 2.9 since 2.9 occurs 2 times.16 Midrange, MR = 0 . 0 9 + 1 3 . 0 2 2 l o w e s t v a l u e + h i g h e s t v a l u e 2 Hence the right answer is Option C Click Here To Go Back The table shows the details of the total number of students enrolling in a college in 1965.. 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