Question: The net worth (in millions of dollars) of 30 business units in a city are shown in the frequency distribution. Net worth Frequency 15 - 25 3 26 - 36 10 37 - 47 12 48 - 58 5
Find the mean and the mode of the data and compare them. A ) 38, 37, mean > mode B ) 284.75, 284.75, mean = mode C ) 37.97, 42, mean < mode D ) 284.75, 37, mean > mode Steps to derive 1 The midpoint of each class (net worth) and the product with the frequency is as shown in the table.2 Mean (X ‾ ) = 1 n ∑ f X = 1139 30 = 37.97 [Use n = ∑ f .]3 The modal class is 37 - 47, since it has the largest frequency. The mode of the date is 3 7 + 4 7 2 = 42.4 The mean of the net worth (in millions of dollars) of 30 business units is 37.97 and the mode of the data is 42.5 So, mean < mode. [Compare the values of mean and mode.]Hence the right answer is Option C Click Here To Go Back Few Other Questions - Which of the following Venn diagrams represents the correct relationship between scalene t.. Evaluate 4y - z23 for y = 25 and z = 8... Find the ordered pair, which is the solution of the equation -y = 3x + 2... The central angle of a sector is 20o. 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