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Question: The points (- 3, 0), (2, 0), (0, 3) are joined by line segments to create the polygonal region, then which system of linear inequalities defines the polygonal region?


A ) y ≥ 0, yx + 3, 2y ≤ - 3x + 6
B ) y ≥ 0, yx + 3, 2y ≤ - 3x + 6
C ) y ≤ 0, yx + 3, 2y ≥ - 3x + 6
D ) y ≤ 0, yx + 3, 2y ≥ - 3x + 6

Steps to derive

1 Plot the points (- 3, 0), (2, 0), (0, 3) and join by line segments to create a polygonal region.



3 Line (1) passes through the points (- 3, 0) and (0, 3).

4 m = y2 -y1x2 -x1 = 3 - 00 - (-3) = 1
 [Substitute coordinates into slope formula and simplify.]

5 As the line (1) crosses y-axis at (0, 3), the y-intercept is 3.

6 y = mx + b
 [Write slope-intercept form.]

7 y = x + 3
 [Replace m with 1 and b with 3.]

8 Since, the shaded region is below the solid boundary line (1), the inequality is yx + 3.

9 Line (2) passes through the points (0, 3) and (2, 0).

10 m = y2 -y1x2 -x1 = 0 - 32 - 0 = - 32
 [Substitute coordinates into slope formula and simplify.]

11 Line (2) crosses the y-axis at (0, 3), so y-intercept is 3.

12 y = mx + b
 [Write slope-intercept form.]

13 y = - 32x + 3
 [Replace m with - 32 and b with 3.]

14 2y = - 3x + 6
 [Simplify.]

15 Since the shaded region is below the solid boundary line (2), the inequality is 2y ≤ - 3x + 6.

16 The equation of line (3) is y = 0.

17 Since the shaded region is above the solid boundary line (3), the inequality is y ≥ 0.

18 The system of inequalities that describes the polygonal region is y ≥ 0, yx + 3, 2y ≤ - 3x + 6.



Hence the right answer is Option B

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