Question: The points (- 3, 0), (2, 0), (0, 3) are joined by line segments to create the polygonal region, then which system of linear inequalities defines the polygonal region? A ) y ≥ 0, y ≥ x + 3, 2y ≤ - 3x + 6 B ) y ≥ 0, y ≤ x + 3, 2y ≤ - 3x + 6 C ) y ≤ 0, y ≤ x + 3, 2y ≥ - 3x + 6 D ) y ≤ 0, y ≥ x + 3, 2y ≥ - 3x + 6 Steps to derive 1 Plot the points (- 3, 0), (2, 0), (0, 3) and join by line segments to create a polygonal region.3 Line (1) passes through the points (- 3, 0) and (0, 3).4 m = y 2 - y 1 x 2 - x 1 = 3 - 0 0 - ( - 3 ) = 1 [Substitute coordinates into slope formula and simplify.]5 As the line (1) crosses y -axis at (0, 3), the y -intercept is 3.6 y = m x + b [Write slope-intercept form.]7 y = x + 3 [Replace m with 1 and b with 3.]8 Since, the shaded region is below the solid boundary line (1), the inequality is y ≤ x + 3.9 Line (2) passes through the points (0, 3) and (2, 0).10 m = y 2 - y 1 x 2 - x 1 = 0 - 3 2 - 0 = - 3 2 [Substitute coordinates into slope formula and simplify.]11 Line (2) crosses the y -axis at (0, 3), so y -intercept is 3.12 y = m x + b [Write slope-intercept form.]13 y = - 3 2 x + 3 [Replace m with - 3 2 and b with 3.]14 2y = - 3x + 6 [Simplify.]15 Since the shaded region is below the solid boundary line (2), the inequality is 2y ≤ - 3x + 6.16 The equation of line (3) is y = 0.17 Since the shaded region is above the solid boundary line (3), the inequality is y ≥ 0.18 The system of inequalities that describes the polygonal region is y ≥ 0, y ≤ x + 3, 2y ≤ - 3x + 6.Hence the right answer is Option B Click Here To Go Back Few Other Questions - Find the product of 4y5 and (10y4 - 6y + 5)... 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