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Question: The sides of a regular hexagon are extended to form 6 congruent triangles. If the length of one side of the hexagon is 10 cm, then find the total area of the figure in sq.cm. A ) 3503 sq.cm B ) 3003 sq.cm C ) 4003 sq.cm D ) 102 sq.cm Steps to derive 2 ABCDEF is the hexagon [Figure.]3 m ∠ PAB = m ∠ PBA = 60 [m ∠ EAB = m ∠ CBA = 120.]4 ΔPAB is equilateral [Step 3.]5 Area of the figure = Area of the hexagon + area of 6 equilateral triangles6 = 12 × area of one equilateral triangle7 = 12 × 3 4 × 10 × 108 = 3003 sq.cmHence the right answer is Option B Click Here To Go Back Few Other Questions - The tallest person in the army is 7634 in. high. He is 712 in. taller than the shortest pe.. Solve for the variable in the equation. 2a = - 6.. Jim rented a beach cabin at $8 for each day of stay. He paid $64 towards rent. Solve the e.. Simplify 7a + b + 3a - 10b... Evaluate the expression 60... Evaluate the expression (25)0... Evaluate the expression (0.9)0... 20 - 3 = _______.. 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