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Trigonometric Identities and Equations -Solving Trigonometric Equations
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Question: The value of the expression
3
cosec 20° - sec 20° is equal to _______
A ) 4
B ) 2
C )
2
sin
2
0
°
sin
4
0
°
D )
4
sin
2
0
°
sin
2
0
°
Steps to derive
1
Given
3
cosec 20° - sec 20°
2
=
3
sin
2
0
°
-
1
cos
2
0
°
[Use cosec θ =
1
sin
θ
and sec θ =
1
cos
θ
.]
3
=
3
cos
2
0
°
-
sin
2
0
°
sin
2
0
°
cos
2
0
°
[Simplify.]
4
=
2
[
3
2
cos
2
0
°
-
1
2
sin
2
0
°
]
2
2
sin
2
0
°
cos
2
0
°
[Multiply and divide the numerator and denominator by 2.]
5
=
4
[
3
2
cos
2
0
°
-
1
2
sin
2
0
°
]
sin
4
0
°
[Use 2sin A cos A = sin 2A.]
6
=
4
(
sin
6
0
°
cos
2
0
°
-
cos
6
0
°
sin
2
0
°
)
sin
4
0
°
[Use
3
2
as sin 60° and
1
2
as cos 60°.]
7
4
[
sin
(
6
0
°
-
2
0
°
)
]
sin
4
0
°
[Use sin A cos B - cosA sin B = sin (A - B).]
8
4
(
sin
4
0
°
)
sin
4
0
°
= 4
[Simplify.]
9
Therefore the value of the expression
3
cosec 20° - sec 20° is 4.
Hence the right answer is Option A
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