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Question: There are 6 women and 5 men in a department. How many ways can a committee of 4 people be selected such that there are at least 2 women on the committee? Steps to derive 1 Number of women = 6
2 Number of men = 5
3 We need to have atleast 2 women on the committee. That is (2 women , 2 men) or (3 women, 1 man) or all 4 women.4 Selecting 2 women and 2 men from 6 women and 5 men = 6 C2 × 5 C2 = 1506 C2 = 15,
5 C2 = 10]5 Selecting 3 women and 1 man from 6 women and 5 men = 6 C3 × 5 C1 = 1006 C3 = 20,
5 C1 = 5]6 Selecting all 4 women and 0 men from 6 women and 5 men = 6 C4 × 5 C0 = 156 C4 = 15,
5 C0 = 1]7 Number of ways a committee can be formed having atleast 2 women = 150 + 100 + 15 = 2658 So, a committee of 4 people with atleast 2 women can be selected in 265 ways.Hence the right answer is Option B Click Here To Go Back Which fraction is equal to 1?.. Which fraction is equal to 1?.. Which fraction is equal to 1?.. Identify the property that can be used to explain the statement which follows. - 0.369 + 0.. Which property does the expression 2.65 + 1188 = 1188 + 2.65 illustrate?.. Which property does the equation x + 12 = 12 + x illustrate?.. Identify the property that is true for the statement.(- 3 + 7) + (- 6) = - 3 + (7 + (- 6)).. Which property is illustrated in the expression2.4 × (4.6 × 23.7) = (2.4 &time.. In a geometric series a1 = 243 and 6th term is 32. Find the sum of the first 6 terms... Find ∑n=135n. .. Find ∑k=26(4k - 6)... ∑k=16(5k + 21) = ?.. Find the value of log9 124... Find the value of log9 63... Find the value of log7 28... Evaluate: ∑n=353(4)n - 1.. 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