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Question: Three different companies produce a particular type of electronic component. Random samples of components are selected from each company. Components are put into actual use until they fail and the life time of the components noted are as shown. At α Steps to derive 1 Let μ1 , μ2 , μ3 be the mean lifetime of the components.0 : μ1 = μ2 = μ3 1 : At least one mean is different from the others.2 k N d.f. d.f. N = k d.f. D = N k α k N 3 The mean and variance of each sample are given below the table.4 Grand mean X ‾ GM = Σ X N 4 8 + 5 2 + 6 0 + . . . . . . + 4 8 + 5 2 1 8 850 18 5 Between-group variance SB 2 = Σ n i ( X ‾ i - X ‾ G M ) 2 K - 1 6 SB 2 = 6 ( 5 4 . 1 6 7 - 4 7 . 2 2 ) 2 + 6 ( 3 3 . 5 - 4 7 . 2 2 ) 2 + 6 ( 5 4 - 4 7 . 2 2 ) 2 3 - 1 1 6 9 4 . 8 2 7 Within-group variance SW 2 = Σ ( n i - 1 ) S i 2 Σ ( n i - 1 ) 8 SW 2 = ( 6 - 1 ) ( 4 8 . 1 6 7 ) + ( 6 - 1 ) ( 4 7 . 9 ) + ( 6 - 1 ) ( 2 9 . 2 ) ( 6 - 1 ) + ( 6 - 1 ) + ( 6 - 1 ) 6 2 6 . 3 3 1 5 9 F test value F = S B 2 S W 2 8 4 7 . 3 9 4 1 . 7 5 6 B 2 , SW 2 .]10 Since 20.294 > 2.695, the decision is to reject the null hypothesis.11 There is enough evidence to conclude that at least one mean is different from the others.12 The ANOVA summary table is shown below.Hence the right answer is Option D Click Here To Go Back Determine whether the sequence {2n sin-1 (1n)} converges or diverges. If the sequence conv.. 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