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Question: Using congruency of triangles, prove that diagonals of a parallelogram bisect each other.



Steps to derive

1 Figure:


2 From parallelogram ABCD,

3 ABD CDB

4 DCA CAB
 [Alternate angles are equal.]

5 AB CD & AB || CD

6 AD BC & AD || BC

7 Hence ΔOAB ΔOCD
 [ASA postulate.]

8 Since the two triangles are congruent, OB OD & OA OC

9 So, O is the midpoint of diagonals BD & AC. Hence, diagonals of a parallelogram bisect each other.



Hence the right answer is Option

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