2 sample test

Find the F-test value for testing the difference between two population variances. The data shows the two samples from each of the populations. => 1.11 or 0.63 or 2.38 or 2.16..

If the degrees of freedom of the numerator is 15 and that of the denominator is 24 for testing the variances of two populations using F-test, then find the test value and the critical value at 95% confidence. The sample variances are 45 and 78. => h..

Overview of methods of data collection: Census Sample survey Experiment Observational study Planning and conducting surveys: Characteristics of a well-designed and well-conducted survey Populations, samples, and random selection Sources of bias in s..

A sample of 30 RAM chips was tested for the average access time. The standard deviation was found to be 2 nanosec. Find the 90% confidence interval for the true standard deviation. Assume that the variable is normally distributed. => between 1.7 and 2.6 or be..

Find the F-test value for testing the variances of two populations. The sample variances from those populations are s 1 2 = 15, s 2 2 = 28. => 1.87 or 0.53 or 3.89 or 6.52..

The standard deviation of the annual income of a random sample of 20 doctors in U.S. having one to two years experience is $5900. Test the hypothesis that the standard deviation of the population is more than $5,400 a year at α = 0.05. Also write the chi-square h..

refers to the process of taking instantaneous values of the message signal at regular intervals (in the case of uniform sampling.) This makes the time-frame (of the analog signal) discrete. Most pulse systems are based on sampling of the information signal amplitude at periodi..

Radio tubes manufactured by a company are expected to have a mean lifetime of 400 hours, with a standard deviation of 30 hours. Random samples of 10 tubes were tested. It was found that 3 tubes had a lifetime of 398 hours, 5 of them had a lifetime of 410 hours and 2 ha..

The critical t value for a sample size of 8 is 3.23. The test is two tailed. What is the p -value in the t test? => between 0.01 and 0.02 or between 2.998 and 3.5 or between 0.005 and 0.01 or between 9 and 10..

In a report, the standard deviation of the weights of male student athletes is stated as 2 pounds. The standard deviation of weight of a random sample of 24 male student athletes was found as 1.9 pounds. Find the chi-square test value. At α = 0.01 is there enough..