2cos 2x sinx 1

Evaluate: 2! x (1! + 0!) => 9 or 4 or 6 or 5..

Linear Equations in One Variable - An equation of one variable and of first order (i.e., its highest power is one) is called a Linear equation. Such an equation has only one solution. A solution is also called the 'root' of the given equation.An equation of h..

Find the area of the region bounded by the curves r = 1 and r = 2 cos θ . => 1 2 + π 3 or 3 2 + π 3 or 3 2 - π 3 or π 3 + 1 or 1 2 + π 3..

Graph of Linear Equation in one variable - ax + b = 0 is a linear equation in one variable. Consider the equation 2x + 4 = 0 2x = -4 x = -2 Since this equation is independent of y, for all values of y, x = -..

Evaluate: (6 x 5 x 4 x 3 x 2 x 1) (4 x 3 x 2 x 1)(2 x 1) => 30 or 15 or 8 or 35..

Solve the equation 2cos t = 3sin 2 t . => t = 2 n π + 0.3733 π , n = 0, ± 1, ± 2, . . . or t = 2 n π , n = 0, ± 1, ± 2, . . . or t = 2 n π ± 0.244 π ..

Find the slope of the polar equation r = 1 + 2 cos θ at θ = π 2 . => 2 or 1 or - 1 or 0 or - 2..

Which of the two expressions has a smaller value? 1) 3 + 4 ÷ (5 - 3) × 5 + 4 2) (14 - 2) ÷ 4 + 5 - 2 x 5 => Expression-1 or Expression-2 or Both are equal or Cannot be determined..

Find the area of the region bounded by the graph r 2 = 2cos θ and between the rays θ = - π 6 and π 4 . => 2 + 3 2 square units or 2 + 1 2 square units or 2 + 1 square units or ..

Find the area enclosed by the polar curve r = 2cos θ, where - π 2 ≤ θ ≤ π 2 . => π 2 square units or 0 or ( π + 1) square units or π square units or 2 π square units..