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To find the logarithm of a Complex number
To find the logarithm of a Complex number - Let z= x + iy be a complex number. Taking log on both side..
To find the logarithm of a Complex number - Let z= x + iy be a complex number. Taking log on both side..Complex Numbers Summary
Summary - If x and y are any real numbers, then x+iy is called a complex number. In the complex number x+iy, the real numbers x and y are respectively called the real part and imaginary part of x+iy. Two complex numbers are said to be equal if their real..
Summary - If x and y are any real numbers, then x+iy is called a complex number. In the complex number x+iy, the real numbers x and y are respectively called the real part and imaginary part of x+iy. Two complex numbers are said to be equal if their real..Graphical representation of Complex numbers
The complex number Z = x + iy may be represented graphically by the point P whose rectangular co-ordinates are (x, y). Thus each point in the plane is associated with a complex number. In the figure, P defines Z = x + iy. It is customary to choose x-axis as real axis and y-axi..
The complex number Z = x + iy may be represented graphically by the point P whose rectangular co-ordinates are (x, y). Thus each point in the plane is associated with a complex number. In the figure, P defines Z = x + iy. It is customary to choose x-axis as real axis and y-axi..To find the logarithm of a Complex number
Let z= x + iy be a complex number. Taking log on both side..
Let z= x + iy be a complex number. Taking log on both side..Irrational numbers 2 Animation
Rational and Irrational Numbers..
Rational and Irrational Numbers..Number Theory - Test Questions
Question 1 - Question: Show that the sum of the cubes of any number of consecutive integers is divisible by the sum of those integers. Answer: Let the consecutive integers be (n + 1), (n + 2), (n + 3),....,(n + m) Sum of the cubes of integers = S 1 (n+m) and (n+m+1) are consecutive intege..
Question 1 - Question: Show that the sum of the cubes of any number of consecutive integers is divisible by the sum of those integers. Answer: Let the consecutive integers be (n + 1), (n + 2), (n + 3),....,(n + m) Sum of the cubes of integers = S 1 (n+m) and (n+m+1) are consecutive intege..Additive inverse of a Complex number
Let Z = a + i b and Z' = x + iy be the additive inverse of Z, then a + x = 0 and b + iy = 0 \ Additive inverse of a + ib is - a - ..
Let Z = a + i b and Z' = x + iy be the additive inverse of Z, then a + x = 0 and b + iy = 0 \ Additive inverse of a + ib is - a - ..Multiplicative identity of Complex numbers
Let Z = a + i b and Z' = x + iy, then ax - by = a ..... (i) and ay + bx = b ..... (ii) Solving (i) and (ii), we have x = 1, y =0 Multiplicative identity is 1 + ..
Let Z = a + i b and Z' = x + iy, then ax - by = a ..... (i) and ay + bx = b ..... (ii) Solving (i) and (ii), we have x = 1, y =0 Multiplicative identity is 1 + .. Result
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