75 confidence interval

An athlete wishes to estimate the mean number of miles run by him per day during practice session. The number of miles run by him on 7 days selected randomly is 7.2, 7, 7.5, 7.8, 7.6, 8 and 7.5. Based on the sample mean, what is the point estimate of the mean? Find the 95% ..

A sample of the reading scores of 35 sixth graders has a mean of 82. If the 95% confidence interval for the population mean of the reading scores of all fifth graders is between 77 and 87, then which among the following choices represents the 99% confidence interv..

The formula for the confidence interval for a standard deviation is ________ . => III or II or IV or I..

When a 95% confidence interval is calculated instead of a 90% confidence interval with the same sample, the maximum error of estimate will be _____ . => either smaller or larger depending on sample size or the same or smaller or larger..

The mean score on a standardized test is 100 with a standard deviation of 8. A random sample of 48 scores was found to have a mean of 98. Find the 95% confidence interval. => The interval is between 97.75 and 102.25 or The interval is between 1.15 a..

If 95% confidence interval for the average age of the club members is 39 < μ < 41, then which of the following could be 99% confidence interval? => 39.4 < μ < 40.6 or 39.5 < μ < 40.5 or 39 < μ < 41 or 38 < μ < 42 o..

Based on a sample of 150 U.S couples, it was found that in 108 couples the children are taller than the couples. Find the 95% confidence interval for the proportion of all U.S couples where children are taller than the parents. => 68.3% < p < 75.7% or 64.8% < ..

Select the correct statement(s). I. Increase in sample size will make the confidence interval of the population mean wider. II. A 90% confidence interval will be wider than a 99% confidence interval. III. Sample mean can never be the same ..

A survey of 120 families showed that at least 78 had a computer at home. Find the 99% confidence interval of the true proportion of families who own a home computer. => 64.5% < p < 65.5% or 5.38% < p < 7.62% or 53.8% < p < 76.2% or 60.6% < p < 69.4%..

The average monthly temperature(°F) of 15 cities in the month of April is shown here. Find the 80% confidence interval for the standard deviation for the temperature. Assume that the variable is normally distributed. 61.6 48.3 47.8 65 47.6 48.1 68.5 52 66 75.7 46.6..