a solution of a certain sixth degree equation is . what is its solution in the simplest form?

A solution of a certain sixth-degree equation is 4 0 9 6 x 1 8 6 . What is its solution in the simplest form? => 4 x 6 or 4 x 3 or 18 x 3 or 5 x 3..

Preparation of Colloidal Sols - For the preparation of lyophilic and lyophobic sols different methods are us..

Purification of Colloidal Sols - The colloidal solutions prepared by various methods usually contain electrolytes and other soluble substances as impurities. These impurities if not removed can destabilize the sols. Impurities are removed by the following methods: 1) D..

The colloidal solutions prepared by various methods usually contain electrolytes and other soluble substances as impurities. These impurities if not removed can destabilize the sols..

Heterogenous nature - Colloidal sols are biphasic in nature. It consists of the dispersed phase and the dispersion medium. In the colloidal solution, each particle is contained within its own surface boundary and therefore has a separate existence from the dispersion mediu..

Preparation of Lyophilic Sols Since lyophilic sols are quite stable, they can be easily prepared by shaking the lyophilic substance with the dispersion medium. Examples are: Colloidal sols of gum, starch, gelatine and egg albumi..

A Solution is a homogeneous mixture of two or more chemically non-reacting substances called components. The composition of the components can be varied with in certain limit..

The degree of hardness of water is defined as the number of parts by mass of calcium carbonate, equivalent to various calcium and magnesium present in one million parts of mass of water. It is expressed in ppm. Now, 10 6 g of water contains CaCO 3 = 44 mg By definition, 1 mol..

Gold being a noble metal occurs in its native form. It is further purified by the process of leaching or precipitiation called hydrometallurgy. The native gold in its complex form is first precipitated with potassium cyanide solution. It is then recovered from the ..

Thus, larger the K a value stronger is the acid. Therefore, 3. Calculate the degree of ionization and [H 3 O + ] of a 0.1 mol /L solution of acetic acid. Given: K a (CH 3 COOH) = 1.8 x 10 - 5 mol /..