Theorem
A statement that requires a proof is called a theorem..
Theorem
Using Binomial theorem, prove that: ..
Using Binomial theorem, prove that: ..Theorem:
If x is a rational number, then the sum (e x ) of the exponential series..
If x is a rational number, then the sum (e x ) of the exponential series..Theorem:
The inverse of a square matrix if it exists, is unique. Let A be an invertible square matrix. If possible, let B and C be two inverse of A. Then AB = BA = I. AC = CA = I (by def. of inverse) Now, B = BI = B(AC) = (BA)C [ Matrix multiplication is associative] = IC = C i.e., B = C Hence the inverse..
The inverse of a square matrix if it exists, is unique. Let A be an invertible square matrix. If possible, let B and C be two inverse of A. Then AB = BA = I. AC = CA = I (by def. of inverse) Now, B = BI = B(AC) = (BA)C [ Matrix multiplication is associative] = IC = C i.e., B = C Hence the inverse..Theorem
..
..Theorem:
The number of combinations of n dissimilar things, taken r at a time is..
The number of combinations of n dissimilar things, taken r at a time is..Theorem
The length of the line segment AB, which joins A (x 1 , y 1 ) and B (x 2 , y 2 ) is given by ..
The length of the line segment AB, which joins A (x 1 , y 1 ) and B (x 2 , y 2 ) is given by ..Theorem
The angle bisectors of a triangle pass through the same point..
The angle bisectors of a triangle pass through the same point..Theorem
If two lines intersect, then the vertically opposite angles are congruen..
Result
Pages   :     1     2     3     4     5     6     7     8     9     10     11
See what our Users say :
My daughter is getting 'A' grade in math, This is a great tutoring ...Thank you Tutor Vista..
I am Jessica from New York, I got excellent English tutors from Tutor Vista, who helped me lot to overcome my grammar mistakes, Thanks a lot...
My son started joined Tutor Vista in 6 th grade, Now he is 8 th grade, He likes Tutor Vista tutors more than his school teachers…Lucy
I asked a Math question in the chat box in tutorvista. I was amazed to see live response from the tutor who helped me with my questions. That was great. I joined their online regular tutoring so that I can get such help anytime. - Mary
Looking for More Help!
