algebraic method vs graphical method


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I Method
Methods of completing a square and to derive the formula for the solution of the quadratic equation. ..
Substitution Method
Solve the Systems of linear equations by Method of Substitution: 2x - 9y = 0 (i) x - 18y = 27 (ii..
Second Method:
x 2 + 8x + 15 = x 2 + 5x + 3x + 15 (after noticing that 5 + 3 = 8 and 5 3 = 15) = x(x +5) + 3(x + 5) = (x + 5) (x + 3) Resolve into factors: x 2 - 15x + 56 x 2 - 15x + 56 Take factors of 56 having their sum = -15 They are -8, -7. \ x 2 - 15x + 56 = x 2 - 7x - 8x + 56 \ x 2 - 15x +..
Second Method:
x 2 - 2x - 48 = x 2 - 8x + 6x - 48 = x(x - 8) + 6(x - 8) = (x - 8) (x + 6) When the coefficient of the highest power is not unity. i.e., type ax 2 bx c, when and b and c are integers. Multiply (3x + 2) (x + 4) and consider the result so obtained. = 3x (x + 4) +2 (x + 4) = 3x 2 + 12x..
Substitution Method
Solve 2x - 9y = 0 (i) x - 18y = 27 (ii) From (i) 2x - 9y = 0 2x = 9y (iii) Substituting this value of x in (ii), we get, 9y - 36y = 54 - 27y = 54 y = -2 Substitute this value of y in (iii): = - 9 The solution is x = -9 and y = -2. Solve 43x + 31y = 241 (i) 31x + 43y = 277 (ii) By a..
Methods of solving quadratic equations
There are four methods of solving quadratic equations. i) By factorization ii) By completing the squares iii) By using the formula iv) By graphi..
Simultaneous Equations-Method of Elimination
Method of Elimination - Solve: 3x - 4y = 20 (i) 5x + 6y = 8 (ii) Multiply (i) by 3 and (ii) by 2: Adding the two, 19x = 76 Substituting x = 4 in (ii), we get 5(4) + 6y = 8 6y = 8 - 20 6y = -12 y = ..
Methods of completing a square and to derive the formula for the solution of the quadratic equation
There are two methods to derive the formula for the solution of the quadratic equation (i) Simple Method and (ii) By Sridhar's Method. The quadratic equation has two root..
Representation of a Function
Representation of a Function - A function can be represented by the following methods:A function can be represented by the following methods..
Summary
Finding the solution by the method of substitution. (i) Coefficients of one of the variables (say x) in the two equations are made equal, by multiplying them with suitable factor..
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