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Tanya was reading a novel, which had 10 chapters. She spent 1 hour(s) ..
Tanya was reading a novel, which had 10 chapters. She spent 1 hour(s) reading the first chapter and took the same amount of time to read all the other chapters of the novel. She completed reading the novel in 19 hours. Solve the equation 1 + 9 h = 19, to find h , the n..
The Life of a Star
The Life of a Star - The life cycle of a star begins with the accretion of hydrogen and helium gas at -173 o C into smaller dense clouds, which contract under their own gravity. This dense cloud of gas contracting under its own gravity is called a Protostar . A cloud of gas from..
The Life of a Star - The life cycle of a star begins with the accretion of hydrogen and helium gas at -173 o C into smaller dense clouds, which contract under their own gravity. This dense cloud of gas contracting under its own gravity is called a Protostar . A cloud of gas from..Definition -Average Life or Mean Life
The total lifetime of all the atoms of the element divided by the total number of atoms present initially in the sample of the element. ..
The total lifetime of all the atoms of the element divided by the total number of atoms present initially in the sample of the element. ..Half-Life Period
The time required for the decay of the radioactive element to one half of its original amount is called Half-Life Period . It is denoted by t 1 / 2 . Putting these values in equation (iii), we get ..
The time required for the decay of the radioactive element to one half of its original amount is called Half-Life Period . It is denoted by t 1 / 2 . Putting these values in equation (iii), we get ..Factorising a3
b3
The product of a + b and a 2 - ab + b 2 is a 3 + b 3 . Hence when a 3 + b 3 is factorised, we get: a 3 + b 3 = (a + b) (a 2 - ab + b 2 ) Similarly, a 3 - b 3 = (a - b) (a 2 + ab + b 2 ) Factorise: x 3 + 8 x 3 + 8 = (x) 3 + (2) 3 = (x + 2) (x 2 - 2x + 4) Factorise 64x 3 - 125. ..
b3 The product of a + b and a 2 - ab + b 2 is a 3 + b 3 . Hence when a 3 + b 3 is factorised, we get: a 3 + b 3 = (a + b) (a 2 - ab + b 2 ) Similarly, a 3 - b 3 = (a - b) (a 2 + ab + b 2 ) Factorise: x 3 + 8 x 3 + 8 = (x) 3 + (2) 3 = (x + 2) (x 2 - 2x + 4) Factorise 64x 3 - 125. ..Final Stages in the Life Cycle of a Star
. A star, whose mass is equal or less than that of the Sun loses its expanding shell and the core condenses into an extremely dense ball of matter and the resulting high temperature favors the fusion of helium nuclei to carbon. The energy liberated by the fusion of helium makes this small core glow..
. A star, whose mass is equal or less than that of the Sun loses its expanding shell and the core condenses into an extremely dense ball of matter and the resulting high temperature favors the fusion of helium nuclei to carbon. The energy liberated by the fusion of helium makes this small core glow..Introduction
Arrangement and selection of objects are the central ideas of this chapter on permutations and combinations. They are widely applied in solving problems of probability, genetic engineering and life scienc..
Introduction to Permutations and Combinations
Introduction - Arrangement and selection of objects are the central ideas of this chapter on permutations and combinations. They are widely applied in solving problems of probability, genetic engineering and life scienc..
Permutations and Combinations
Introduction - Arrangement and selection of objects are the central ideas of this chapter on permutations and combinations. They are widely applied in solving problems of probability, genetic engineering and life science..
Conclusion
Solutions are homogeneous mixtures having great importance in our day to day life. In this chapter we have learnt the various types of solutions, the meaning of vapor pressure, Raoult's Law, Colligative Properties and Abnormal Molecular Mass..
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