Factorising a3
b3
The product of a + b and a 2 - ab + b 2 is a 3 + b 3 . Hence when a 3 + b 3 is factorised, we get: a 3 + b 3 = (a + b) (a 2 - ab + b 2 ) Similarly, a 3 - b 3 = (a - b) (a 2 + ab + b 2 ) Factorise: x 3 + 8 x 3 + 8 = (x) 3 + (2) 3 = (x + 2) (x 2 - 2x + 4) Factorise 64x 3 - 125. ..
b3 The product of a + b and a 2 - ab + b 2 is a 3 + b 3 . Hence when a 3 + b 3 is factorised, we get: a 3 + b 3 = (a + b) (a 2 - ab + b 2 ) Similarly, a 3 - b 3 = (a - b) (a 2 + ab + b 2 ) Factorise: x 3 + 8 x 3 + 8 = (x) 3 + (2) 3 = (x + 2) (x 2 - 2x + 4) Factorise 64x 3 - 125. ..Question 9
Question: Solve the following equation: Answer: 4x + 7 = -3 (2x + 1) (By cross-multiplication) 4x+7=-6x-3 4x+6x=-3-7 10x=-10 x=-..
Question: Solve the following equation: Answer: 4x + 7 = -3 (2x + 1) (By cross-multiplication) 4x+7=-6x-3 4x+6x=-3-7 10x=-10 x=-..
Table 9
Construct the required function as follo..
Construct the required function as follo..Class
Inclusive type of frequency distribution can be converted into exclusive type as in Table (..
Inclusive type of frequency distribution can be converted into exclusive type as in Table (..Examples of terminating decimal:
2.793 represents 2 units, seven-tenths, nine-hundredths and three-thousandths or using fraction notation: (a) (b)..
2.793 represents 2 units, seven-tenths, nine-hundredths and three-thousandths or using fraction notation: (a) (b)..Suggested answer:
Verify by actual multiplication. Verification by actual multiplication: ..
Verify by actual multiplication. Verification by actual multiplication: ..Factorisation using Identities
Recall the following identities for finding the products: Observe that the LHS in the identities are all factors and the RHS are their products. Thus, we can write the factors as follow..
Recall the following identities for finding the products: Observe that the LHS in the identities are all factors and the RHS are their products. Thus, we can write the factors as follow..Suggested answer:
x=35 Antecedent=..
x=35 Antecedent=..
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