Hydraulic Machines
The transmission of power is made use of in hydraulic machines where a small force applied at one point is made to exert a much larger force at some other point. This principle is made use of in the working of a hydraulic press and hydraulic brake..
The transmission of power is made use of in hydraulic machines where a small force applied at one point is made to exert a much larger force at some other point. This principle is made use of in the working of a hydraulic press and hydraulic brake..Common Balance
This balance consists of a beam and two scale pans (shown in figure below), the beam being balanced at its mid point on a knife-edge. The scale pans also hang on knife edges and rest on the base board. When the balance is not in use the beam rests on the beam support...
This balance consists of a beam and two scale pans (shown in figure below), the beam being balanced at its mid point on a knife-edge. The scale pans also hang on knife edges and rest on the base board. When the balance is not in use the beam rests on the beam support...Stationary Waves
Stationary Waves - Stationary or standing waves are formed in a medium when two waves having equal amplitude and frequency moving in opposite directions along the same line, interfere in a confined space. Generally, such waves are formed by the superposition of a forward wave and the reflected wave..
Principle of Moments
Clockwise moment and anticlockwise moment about 50 cm divisions are equal. Suggested answer : 20 x d = 40 x 20 Therefore, Hence the 20 N force of B is acting from 90 cm mark. Example 2: The illustration in figure below shows a uniform metre rule weighing 30 N pivoted on a wedge placed und..
Clockwise moment and anticlockwise moment about 50 cm divisions are equal. Suggested answer : 20 x d = 40 x 20 Therefore, Hence the 20 N force of B is acting from 90 cm mark. Example 2: The illustration in figure below shows a uniform metre rule weighing 30 N pivoted on a wedge placed und..Centre of Gravity
You must have tried to balance your exercise book, saucer or a piece of card board on your finger tips. It will be found that in each case, there is one and only one point at which these objects can be balanced. The point through which the resultant of the weights of all the particles of the body..
General properties of non-contact forces
Forces at a distance Are equal and opposite. Depend upon the distance between the two objects. Depend upon the medium between the two objects for electrical and magnetic forces but not gravitational forces. Forces are described in different names. Some forces are shown in the following d..
Forces at a distance Are equal and opposite. Depend upon the distance between the two objects. Depend upon the medium between the two objects for electrical and magnetic forces but not gravitational forces. Forces are described in different names. Some forces are shown in the following d..Lasers-An Introduction
The laser is an acronym for Light Amplification by Stimulated Emission of Radiation. The laser has been invented and developed in 1959 and 196..
Problem
1. A body weighs 12 kg on a weighing machine on the Earth. If it is taken to the moon, will the weighing machine show any change in reading? If so what is the weight of the body on moon. Solution: There will be a change in the reading shown by the weighing machine. Weight of the object on moon (W ..
1. A body weighs 12 kg on a weighing machine on the Earth. If it is taken to the moon, will the weighing machine show any change in reading? If so what is the weight of the body on moon. Solution: There will be a change in the reading shown by the weighing machine. Weight of the object on moon (W ..Problems
1. Calculate the force of attraction between Earth and the Sun. Solution: Given Mass of the Sun =10 3 2 kg Mass of the Earth = 6x10 2 4 kg Distance between the Sun and Earth = 150x10 9 m..
1. Calculate the force of attraction between Earth and the Sun. Solution: Given Mass of the Sun =10 3 2 kg Mass of the Earth = 6x10 2 4 kg Distance between the Sun and Earth = 150x10 9 m..Problem:
An infinite number of charges each equal to 'q' are placed along with X-axis at x = 1m, x = 2m, x = 4m, x = 8m, and so on. Find the electric potential at the point x = 0 due to this set of charge..
Result
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