applied numerical analysis solution


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Numericals
01. An object of mass 5 kg is lifted up through a distance of 2 meter. What is the work done? Solution: W = F x s Also, force acting on the object is F = mg [Newton's second law of motion] Mass of the object (m) = 5 kg Distance moved = 2m Therefore, Work done = F x s 02. How ..
Numericals
01. A body of mass 2kg is raised to a height of 25m. Calculate the potential energy possessed by the body. Solution: Mass of the body (m) = 2kg Height (h) = 25 m Potential energy of the body = mgh 02. A bag of rice weighs 75kg. To what height is it raised if the work done in lifting it is..
Numericals
01. A man of mass 60 kg runs up a flight of 60 steps in 40 seconds. If each step is 20 cm high, calculate his power. Solution : Since the man runs up a flight of steps, the work done will be equal to the potential energy. Height = height of one step x number of ste..
In inorganic qualitative analysis
ionization constant for NH4OH The concepts of solubility product and common ion effect play an important role in qualitative analysis for the separation of basic radicals (cations) into different groups. Weak acids and weak bases ionise in water slightly and an equilibrium is established in their solutions...
Solution
The total number of sublevels or sub-shells possible in each energy level is equal to the numerical value of 'n'. Thus 'n' = 1 energy level can have only one sublevel which is 'l' = 0 or the 's' orbital, 'n' = 2 energy level can have two sublevels corresponding to 'l' = 0 (s) and 'l' = 1..
Solution:
Force (F) = 25 N Distance moved (S) = 10 m Work done (W) = F x S 03. A work of 250 J is done when a force of 10 N is applied on an object. Calculate the distance through which the object move..
Solution:
W = F x S Force acting on the object is given by F = mg [Newton's second law of motion] Mass of the object (m) = 5 kg Distance moved = 2m Therefore, Work done = F x S = 98 J 02. How much work is done, when a force of 25 N displaces an object through 10 m, in the direction of the force ..
Solution
Water as such is a neutral stable molecule. It is difficult to break the covalent O-H bonds easily. Hence, electrical energy through the electrolysis process is applied to separate dioxygen from water. When a small amount of acid is added to water ionization is initiated which helps in e..
Solution
Lithium and Sodium act as strong reducing agents. So, they reduce some metallic chlorides and oxides into metals easily. This property is applied in the preparation of some metals. For example, beryllium, uranium etc., can be obtained by the reduction of the corresponding halides using s..
Atoms and Nuclei Problems - Numerical 12
12. - The half-life of 92 U 238 against alpha decay is 4.5 x 109 years. How many disintegrations per second occur in 1 g of 92 U 238 ? Suggested solution: Again, since one k mole of any isotope contains Avogadro's number of atoms, there fore 1 g of 92 U 238 contains Half life T = 4.5 10 9..
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