average deviation vs standard deviation


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Standard Deviation
Standard Deviation of a statistical data is defined as the positive square root of the arithmetic mean of the squared deviations of items from their arithmetic mean of the series under consideration. The standard deviation is denoted b..
Standard Deviation
of a statistical data is defined as the positive square root of the arithmetic mean of the squared deviations of items from their arithmetic mean of the series under consideration. The standard deviation is denoted by s (sigma). The standard deviatio..
Standard Deviation for continuous series
In this series too deviations may be taken either from the actual mean or from standard mean. The calculations will be simplified if the deviation are taken from assumed me..
Standard Deviation for continuous series
In this series too deviations may be taken either from the actual mean or from standard mean. The calculations will be simplified if the deviation are taken from assumed mea..
Merits and Demerits of standard deviation
Merits: s is based on every item of the data. s takes care of both positive and negative deviation. Demerits: s is some what not easy to understand. The extreme values unduly affect s..
The average score on a Geography final examination was 70, with a stan..
The average score on a Geography final examination was 70, with a standard deviation of 5. The average score on an English final examination was 85 with a standard deviation of 8. Which class was more variable? => English or cannot be dete..
Mean Deviation
The mean deviation of a statistical data is defined as the arithmetic mean of the numerical values of the deviations of items from some average value. Mean deviation is also known as average deviation . The mean d..
Calculation of Standard Deviation for discrete series
In the discrete series, when deviations are taken from actual mean, the formula ..
The average monthly insurance premium paid by 15 managers is $90 with ..
The average monthly insurance premium paid by 15 managers is $90 with a standard deviation of $5. 31 officers pay an average of $65 with the standard deviation of $8.63. At 90% confidence, find the test value. Do the managers pay less ..
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