avogadro;s number


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1st method:
9x - 4x = 13y + 11y 5x = 24 y Squaring both sides, (Componendo and Dividendo) Again Ans: (i) (ii..
Note 4:
The last term in L.H.S of (ii) and (iii)will depend on the fact as to whether n is even or od..
Step 5:
Put the value of r in the term T r + 1 . This gives the required particular term(s..
Number Theory - Test Questions
Question 1 - Question: Show that the sum of the cubes of any number of consecutive integers is divisible by the sum of those integers. Answer: Let the consecutive integers be (n + 1), (n + 2), (n + 3),....,(n + m) Sum of the cubes of integers = S 1 (n+m) and (n+m+1) are consecut..
Sigma Notation
The Greek letter S (read as sigma) denotes the sum. When written before the n t h term of series, implies, the sum of all terms obtained by giving to n the different values 1,2,3..
Basic Definitions
: Two sets A and B are said to be equal if and only if they contain the same elements i.e. if every element of A is in B and every element of B is in A. We denote the equality by A = B. Cardinality of a Set A: The number of elements in a finite set A, is the cardinality of A and is denote..
Introduction
Lets say there are 6 frogs and 2 crabs in a pond. We can compare the number of frogs to the number of crabs in two different ways: How many more frogs than crabs are there? or How many fewer crabs than frogs are there? The answer to both the questions is same i.e. 6-2=..
Suggested answer:
Let S n = 1+2+3+4+...+n This series is an A.P. Here a=1, d=1, l = t n = n 2. To find the sum to squares of first n natural numbers. or..
Sequences and Series Summary
(iii) If 'a' and 'd' be the first term and common difference of the A.P. {T n }, then the sum of first n terms, S n is given by The form (a) is used when common difference 'd' is known and the form (b) is used when the last term 'l' is known. (iv) T 1 = S 1 and for n > 1, we ..
Approximation
Approximation - We know that the digits of a number, one by one in order from left to right decrease in value rapidly. Let us illustrate it by examples. Mass of a gold ornament is 23.473 g. Round off to (i) two decimal places, (ii) one decimal place. 23.473 g = (2 x 10) + (3 x 1) + The su..
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