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Perhaps 'he' was a wildlife photographer who wanted to take some candid shots or maybe, he was a poacher, in pursuit of birds and animals. 9. From the paragraph - 2, pick out words or phrases that suggest motio..
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Perhaps 'he' was a wildlife photographer who wanted to take some candid shots or maybe, he was a poacher, in pursuit of birds and animals. 9. From the paragraph - 2, pick out words or phrases that suggest motio..
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Parmesh and his friends / planning a trip a) were during the summer vacations. While all of them / b) were keen to get away from the heat, none / them were able to suggest which place to visit. c) of It / only draw of lots which could finally decide the matter. d) was They decide..
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Arrhenius equation is ln k= ln A - E a / R T T 1 = 700K, T 2 = 760K, k 1 = 0.011M - 1 s - 1 , k 2 = 0.105 M - 1 s - 1 Substitution of these values in the equation gives = 166.311 KJ / mol ln A = 24.06 A = 2.8 x 10 1 0 M - 1 s - 1 Example12: What is the activation e..
Arrhenius equation is ln k= ln A - E a / R T T 1 = 700K, T 2 = 760K, k 1 = 0.011M - 1 s - 1 , k 2 = 0.105 M - 1 s - 1 Substitution of these values in the equation gives = 166.311 KJ / mol ln A = 24.06 A = 2.8 x 10 1 0 M - 1 s - 1 Example12: What is the activation e..Suggested answer:
where k 2 is the rate constant at 310k and k 1 is the rate constant at 300k. This example shows that for a 10 o rise in temperature near the room temperature results in doubling of the rate of the reacti..
where k 2 is the rate constant at 310k and k 1 is the rate constant at 300k. This example shows that for a 10 o rise in temperature near the room temperature results in doubling of the rate of the reacti..Suggested answer:
The plot of concentration versus time is shown in below figure. The instantaneous rates were calculated at times 6.5 hours and 16.2 hours. The rates are, at time = 6.5 hours = 0.39 M / hr at time = 16.2 hours = 0.23 M / hr fig 6..
The plot of concentration versus time is shown in below figure. The instantaneous rates were calculated at times 6.5 hours and 16.2 hours. The rates are, at time = 6.5 hours = 0.39 M / hr at time = 16.2 hours = 0.23 M / hr fig 6..Suggested answer:
It is assumed that level of carbon-14 in the atmosphere is constant. Since radioactive decay follows 1 s t order kinetics, the ratio carbon-14 in the wood and the carbon-14 in the atmosphere is given by = 4943 years The age of the tree is 4943 year..
It is assumed that level of carbon-14 in the atmosphere is constant. Since radioactive decay follows 1 s t order kinetics, the ratio carbon-14 in the wood and the carbon-14 in the atmosphere is given by = 4943 years The age of the tree is 4943 year..Suggested solution:
For NaCl structure (coordination number 6), the range of radius ratio For maximum possible radius or anion B - the radius ratio will be the minimum, i.e., 0.414. ..
For NaCl structure (coordination number 6), the range of radius ratio For maximum possible radius or anion B - the radius ratio will be the minimum, i.e., 0.414. ..Suggested solution:
In body-centered cubic unit cell, the radius r of the atom is related to the edge of the unit cell by the relation. ..
In body-centered cubic unit cell, the radius r of the atom is related to the edge of the unit cell by the relation. ..Suggested solution:
Radius ratio is in 0.225 - 0.414 range which is for tetrahedral. It crystallizes in ZnS type of structure Coordination number of A+ ion changes from 6 (in NaCl) to 4 (in ZnS type of structur..
Radius ratio is in 0.225 - 0.414 range which is for tetrahedral. It crystallizes in ZnS type of structure Coordination number of A+ ion changes from 6 (in NaCl) to 4 (in ZnS type of structur..See what our Users say :
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