Product Rule for Differentiation
'Derivative of the product of two functions = first function x derivative of second function + second function x derivative of first function..
Product Rule for Differentiation
Let y = u. v, where both u and v are differentiable functions of x.Let y = u. v, where both u and v are differentiable functions of x. or (u.v)' = u.v' + v .u' It can be remembered ..
Let y = u. v, where both u and v are differentiable functions of x.Let y = u. v, where both u and v are differentiable functions of x. or (u.v)' = u.v' + v .u' It can be remembered ..Integration by Parts
In calculus, and more generally in mathematical analysis, integration by parts is a rule that transforms the integral of products of functions into other, possibly simpler, integrals. The rule arises from the product rule of differen..
In calculus, and more generally in mathematical analysis, integration by parts is a rule that transforms the integral of products of functions into other, possibly simpler, integrals. The rule arises from the product rule of differen..Proof:
LHS = F(a) - F(b) = - [F(b) - F(a)] 2)..
LHS = F(a) - F(b) = - [F(b) - F(a)] 2)..Proof:
RHS = F(b) - F(a) + F(c) - F(b) = F(c) - F(a) ..
RHS = F(b) - F(a) + F(c) - F(b) = F(c) - F(a) ..Proof:
= I 1 + I 2 Let us evaluate I 2 Let 2a - x = t When x = 0, t = 2a When x = a, t = a = L.H.S..
= I 1 + I 2 Let us evaluate I 2 Let 2a - x = t When x = 0, t = 2a When x = a, t = a = L.H.S..Proof:
= I 1 + I 2 When f (x) = f (-x) Let -x =t, -dx = dt or dx = -dt When x = -a , t = a x = 0, t = 0 When f (x) = -f (-x), proceeding as above Let -x = t, -dx = dt or dx = -dt When x = -a, t = a x = 0, t = 0 \ I = I 1 + I 2 ..
= I 1 + I 2 When f (x) = f (-x) Let -x =t, -dx = dt or dx = -dt When x = -a , t = a x = 0, t = 0 When f (x) = -f (-x), proceeding as above Let -x = t, -dx = dt or dx = -dt When x = -a, t = a x = 0, t = 0 \ I = I 1 + I 2 ..Proof:
Let log e a = b, \ e b = a ..
Let log e a = b, \ e b = a ..Proof:
Since g is continuous at c, we have Again, f is continuous at g(c) and so Hence fog is continuous at ..
Since g is continuous at c, we have Again, f is continuous at g(c) and so Hence fog is continuous at ..Proof:
Let the two indefinite integrals be..
Let the two indefinite integrals be..See what our Users say :
I really liked this tutoring. Helped me alot and gave me more ways to work a problem. awesome help and I even got the idea on these problems - kimi
I was very pleased with my sessions the tutors were a great help and helped me through the problems step by step - Molly
I need tutoring from tutorvista till th end of my schooling. Tutors are not only experts they are brilliant enough to make a student like me understand the concepts of differentiation and functions.
I could not get time to help my daughter with her homework so I looked on net about online tutoring, we tried tutorvista for a week, my daughter liked it, so, now I got her join it.
Looking for More Help!
