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Approximations by Differentials
Let y = f (x) be a differentiable function of x, errors in x and y are denoted by d x and d y, we have \ Error in y = f ' (x) d ..
Note 4:
dx and dy are called the differentials of x and y respectivel..
Solution:
Let y = f (x) = x 1 / 4 Let x = 81, d x =1. Taking these values we have ..
Symmetry
a) Symmetry about x - axis If the equation of the curve remains unaltered when y is replaced by -y, then the curve is symmetrical about x-axis. b) Symmetry about y-axis If the equation of the curve remains unaltered when x is replaced by -x then the curve is symmetrical about y-axis. c) Symmetry a..
Solution:
Symmetry (a) By replacing y by -y, the equation (1) is altered, therefore the curve is not symmetrical about x-axis. (b) By replacing x by -x, the equation of the curve is altered, therefore the curve is not symmetrical about y-axis. (c) Replace x and y by -x and -y respectively in the equation y ..
Points of intersection
The points of intersection with x-axis is determined by letting y = 0. Putting y = 0, - sin 2x = 0 This implies the curve intersects the x-axis at the points where The points at which the tangent is parallel to x-axes are determined by solving. y = - sin 2x The tangent is paral..
Increasing and Decreasing Functions
This section explains how derivative can be used to check whether a function is increasing, decreasing or neither increasing nor decreasing in its domain. Let f be a function defined on an interval I and let x 1 and x 2 be any two points on I. (i) f is said to be increasing in the interval ..
Theorem 1:
Let f be continuous on [a, b] and differentiable on the open interval (a, b). Then (a) f is increasing on [a, b] if f '(x) > 0 for each x (a, b) (b) f is decreasing on [a, b] if f '(x) < 0 for each x (a, b) This theorem can be proved by using Mean Value Theorem. We shall prove the theore..
Example:
Find the intervals on which the function (a) increasing (b) decreasing Differentiating the function, we have The critical values in ascending order are -1, 1. We divide the Real numbers into the intervals = - ve Since f '(x) < 0, the function is decreasing in the interval ..
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