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X-Ray Emission
And 'E' ranges from 0 to eV. This explains the origin of continuous X-ra..
Properties and uses of X-rays
X-Rays follow a rectilinear propagation and travel with a velocity of 3 x 10 8 ms - 1 in vacuum. They are not deflected by electric and magnetic field. Since they do not contain any charge but are diffracted by crystals, X-rays cause fluorescence when incident on ce..
Result involving product of powers of observed quantities
Relative error in an is n times the relative error a It can be proved that maximum relative error in X, Also, maximum percentage error in X, Maximum percentage error in X = l times maximum percentage error in a + m times maximum percentage error in b + n times..
Result involving sum of two observed quantities
X is the sum of 2 observed quantities a and b. X = a + b Maximum absolute error in X = Maximum absolute error in a + Maximum absolute error i..
Physical Meaning of Angular Momentum
Physical Meaning of Angular Momentum - Consider a particle capable of rotation about an axis. At any time t, let its momentum be and , the position vector. Then the angular momentum is given by the cross product and . = x..
Result involving difference of two observed quantities
Suppose X = a - b Let D a and D b be absolute errors in measurements of quantities a and b, values of a and b and D X be maximum error in X. Maximum absolute error in X = Maximum absolute error in a + Maximum absolute error in b From equations (1) and..
Suggested answer:
= 1.13 x 10 8 m ..
Suggested solution:
The intensity I at a point on the screen where the two disturbances arrive having a phase difference s is I = 0.751 m a x Therefore, Let x be the minimum distance of this point from the central fringe. Then, or..
Suggested answer:
(a) Capacitance in vacuum = 3.54 x 10 - 9 F (b) Charge on each plate = 3.54 x 10 - 9 x 10 4 C = 3.54 x 10 - 5 C (c) Charge density on each plate = 1.77 x 10 - 5 Cm - 2 (d) Field Intensity (e) Field displacement = 1.77 x 1..
Suggested solution:
N = 400 L = 40cm = 0.4m I = 2A The magnetic field at the mid-point is = 2.438 x 10 - 3..
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