Trigonometrical Identities
The trigonometric ratio's are: Sine, Cosine, Tangent, Cotangent, Secant, and Cosecan..
Some Trigonometrical Identities
Some Trigonometrical Identities - 1. sin A = cos (90 o - A) 2. 3. tan A x tan (90 o - A) = 1 4. sin 2 A + cos 2 A = 1 5. 1 + tan 2 A = sec 2 A 6. 1 + cot 2 A = cosec 2 A Let us prove the above identities. Let D ABC be a right-angled triangle with B = 90 o . Let BC = a,..
Some Trigonometrical Identities - 1. sin A = cos (90 o - A) 2. 3. tan A x tan (90 o - A) = 1 4. sin 2 A + cos 2 A = 1 5. 1 + tan 2 A = sec 2 A 6. 1 + cot 2 A = cosec 2 A Let us prove the above identities. Let D ABC be a right-angled triangle with B = 90 o . Let BC = a,..Some Trigonometrical Identities
1. sin A = cos (90 o - A). 2. sin A / cos a = tan A. 3. tan A x tan (90 o - A) = 1. 4. sin 2 A + cos 2 A = 1. 5. 1 + tan 2 A = sec 2 A. 6. 1 + cot 2 A = cosec 2 A. Where 'A' is the angl..
Conditional Trigonometric Identities
Conditional Trigonometric Identities - In the previous sections many identities have been discussed. They are true for all values of the angles for which trigonometric functions are defined. In this section we prove identities, where a certain relat..
Conditional Trigonometric Identities - In the previous sections many identities have been discussed. They are true for all values of the angles for which trigonometric functions are defined. In this section we prove identities, where a certain relat..Conditional Trigonometric Identities
In the previous sections many identities have been discussed. They are true for all values of the angles for which trigonometric functions are defined. In this section we prove identities, where a certain relationship exists among the angles considered. Many interestin..
In the previous sections many identities have been discussed. They are true for all values of the angles for which trigonometric functions are defined. In this section we prove identities, where a certain relationship exists among the angles considered. Many interestin..Trigonometrical Identities Summary
Summary - sin A = cos (90 o - A) tan A . tan (90 o - A) = 1 sin 2 A + cos 2 A = 1 1 + tan 2 A = sec 2 A 1 + cot 2 A = cosec 2..
Summary - sin A = cos (90 o - A) tan A . tan (90 o - A) = 1 sin 2 A + cos 2 A = 1 1 + tan 2 A = sec 2 A 1 + cot 2 A = cosec 2..Trigonometric functions and it's properties
- Identical properties of circular functions and trigonometric functions. Let O be the origin. Let OA be the unit radius of the circle drawn with O as centre. Let OA trace an angle when OA takes the position OP. Then The tracing of the angle q and the arc AP = P( q ) are one and..
- Identical properties of circular functions and trigonometric functions. Let O be the origin. Let OA be the unit radius of the circle drawn with O as centre. Let OA trace an angle when OA takes the position OP. Then The tracing of the angle q and the arc AP = P( q ) are one and..TRIGONOMETRY
Degree/radian measures Basic trigonometric functions Special right triangles Trigonometric values of standard angles Justify the Pythagorean identities Trigonometric equations (0 to 360 degrees..
Circular Functions
The circular functions are functions of an angle. They are important in the study of triangles and modeling periodic phenomena, among many other applications. Trigonometric functions are commonly defined as ratios of two sides of a right triangle containing the angle, and ..
Factorization
Writing a polynomial as the product of two or more polynomials is called factorisation. If A = B x C, B and C are called factors of A. Most of the polynomials can be factorised by grouping the terms suitably and taking out the common factors. Identities studied in the previous..
Result
Pages   :     1     2     3     4     5     6
See what our Users say :
Unlimited tutoring for 24/7 in all the subjects, It's a great help for my kids.
I am Jessica from New York, I got excellent English tutors from Tutor Vista, who helped me lot to overcome my grammar mistakes, Thanks a lot...
Tutor Vista is the only place which gives me accurate answers, you are awesome…Thank you - Mary
I got a very good score in GED because of your great tutors, Thank you Tutor Vista - Pam
Looking for More Help!
