Proof:
In triangles AOB and COD, AO = CO (given) BO = OD (given) (vertically opposite angles are equal) D AOB D COD (SAS congruency condition) Since these are alternate angles made by the transversal AC intersecting AB and CD. AB||CD Similarly, AD||BC Hence ABCD is a parallelogra..
In triangles AOB and COD, AO = CO (given) BO = OD (given) (vertically opposite angles are equal) D AOB D COD (SAS congruency condition) Since these are alternate angles made by the transversal AC intersecting AB and CD. AB||CD Similarly, AD||BC Hence ABCD is a parallelogra..Proof:
A rhombus is a parallelogram such that AB=DC=AD=BC ---(i) Also the diagonals of a parallelogram bisect each other. Hence BO=DO and AO=OC ---(ii) Now compare triangles AOB and AOD, AB=AD (from (i) above) BO=DO (from (ii) above) AO=AO (common side) (SSS congruency condition) (corr..
A rhombus is a parallelogram such that AB=DC=AD=BC ---(i) Also the diagonals of a parallelogram bisect each other. Hence BO=DO and AO=OC ---(ii) Now compare triangles AOB and AOD, AB=AD (from (i) above) BO=DO (from (ii) above) AO=AO (common side) (SSS congruency condition) (corr..See what our Users say :
i really understood it and this teachers left me amazed and opened my eyes to the real world of math! Thanks a lot ,i mean it - Alina
Tutor Vista perceived the math apps well and I enjoyed getting to work with Tutor Vista - Savannah
I really liked this tutoring. Helped me alot and gave me more ways to work a problem. awesome help and I even got the idea on these problems - kimi
very helpful of a complex problem, oh my god I would have never completed this problem with out the tutor. Tutor vista thank u so much.