Construction - 1
Construction - 1 - To construct an angle equal to a given angle and a point Q on a line PQ. An angle equal to at Q. (i) With B as centre and any suitable radius draw an arc to cut AB at D and BC at E. (ii) With Q as centre and the same radius, draw an arc to cut PQ at ..
Construction - 12
Construction - 12 - To construct when , AC = 4 cm, BC = 4.8 cm, two sides and the angle opposite to one of them are given. (1) Draw a straight line AX (2) At A, Construct (3) From A, cut off AC = 4 cm. (4) From C, cut off CB = 4.8 cm, B lying on AX. (5) Then ..
Construction - 12 - To construct when , AC = 4 cm, BC = 4.8 cm, two sides and the angle opposite to one of them are given. (1) Draw a straight line AX (2) At A, Construct (3) From A, cut off AC = 4 cm. (4) From C, cut off CB = 4.8 cm, B lying on AX. (5) Then ..Construction - 12
To construct when , AC = 4 cm, BC = 4.8 cm, two sides and the angle opposite to one of them are given. (1) Draw a straight line AX (2) At A, Construct (3) From A, cut off AC = 4 cm. (4) From C, cut off CB = 4.8 cm, B lying on AX. (5) Then D ABC is the required triangle..
To construct when , AC = 4 cm, BC = 4.8 cm, two sides and the angle opposite to one of them are given. (1) Draw a straight line AX (2) At A, Construct (3) From A, cut off AC = 4 cm. (4) From C, cut off CB = 4.8 cm, B lying on AX. (5) Then D ABC is the required triangle..Construction - 2
Construction - 2 - To bisect an angle , we are required to bisect (i) With B as centre and any suitable radius draw an arc to cut AB at D and BC at E respectively. (ii) Take any radius greater than of ED, not necessarily the previous radius. (iii) With this radius, taking points..
Construction - 2 - To bisect an angle , we are required to bisect (i) With B as centre and any suitable radius draw an arc to cut AB at D and BC at E respectively. (ii) Take any radius greater than of ED, not necessarily the previous radius. (iii) With this radius, taking points..Construction - 6
Construction - 6 - To bisect a given line segment AB is a line segment. The bisector of AB. (i) With A as centre and a suitable radius greater than AB of length, draw arcs on either side of AB. (ii) With the same radius and B as centre, cut the previous pair of arcs at points P ..
Construction of a Rectangle
Diagonal and the angle included by them are given. A Rectangle ABCD, given AC = 7cm, BC = 7 cm and the angle included by them is 60 o . (i) Draw AC = 7 cm. (ii) Construct its perpendicular bisector to obtain the midpoint O. (iii) At O, construct COX = 60 o and prod..
Diagonal and the angle included by them are given. A Rectangle ABCD, given AC = 7cm, BC = 7 cm and the angle included by them is 60 o . (i) Draw AC = 7 cm. (ii) Construct its perpendicular bisector to obtain the midpoint O. (iii) At O, construct COX = 60 o and prod..Construction - 17
). At Y, make an angle of 30 o ( ). Produce their arms to meet at A. (3) Draw perpendicular bisectors of AX and AY to meet XY at B and C. (4) Join AB and AC. Then is the required triangl..
). At Y, make an angle of 30 o ( ). Produce their arms to meet at A. (3) Draw perpendicular bisectors of AX and AY to meet XY at B and C. (4) Join AB and AC. Then is the required triangl..Simple Construction - Test Questions
Question 1 - Question: Answer: Steps of Construction: Step 1: Draw a rough sketch as shown in figure and mark the given measurements. Step 2: Draw a line XY and on it cut off BC = 3.5cm. Step 3: Step 4: Cut off a length BD=5.5cm on BY. Step 5: Join CD. Step 6: Draw the perpendicular bisec..
Question 1 - Question: Answer: Steps of Construction: Step 1: Draw a rough sketch as shown in figure and mark the given measurements. Step 2: Draw a line XY and on it cut off BC = 3.5cm. Step 3: Step 4: Cut off a length BD=5.5cm on BY. Step 5: Join CD. Step 6: Draw the perpendicular bisec..Simple Construction Summary
Summary - Construction of an angle equal to a given angle. Bisecting an angle To construct angles 60 o , 120 o and 30 o . To construct angles 90 o , 45 o and 135 o . To construct angles 75 o and 105 o . Drawing the perpendicular bisector of line segment AB. h..
Multiply: - 24 · 16
Multiply: - 24 · 16 => - 324 or 324 or 384 or - 384..
Result
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