cosecant x

- 1 x For x R - (-1,1), if q is an angle whose cosecant is x, then we say that cosecant inverse of x is q and write cosec -1 x = q . In particular, if q [ -p/ 2, p /2] - {0}, then q is called th..

Write the number of solutions of the equation sin 7 x - cosec 7 x = 0, if 0° ≤ x ≤ 360°. => 3 or 2 or 0 or 1..

Identify the statement which is not true for y = cosec x . => Range is (- ∞, - 1) ∪ [1, ∞]. or The maximum value is y = - 1 and minimum value is y = 1. or Domain is the set of all real numbers. or Period is 2 π ...

Factor the expression 6cot 2 x - 6 tan x + cos x · cosec x . => cot x (6cot x + 5 ) or cot x (6cot x - 5 ) or cot x (cot x - 5 ) or cot x (cot x + 5 )..

If g ( x ) = (4 x 2 + 5 x )cosec 6 x , then find g ′ ( x ). => (8 x + 5)(cosec 6 x ) + (24 x 2 + 30)(cosec 6 x )(cot 6 x ) or (30)(cosec 6 x )(cot 6 ..

If I = ∫ sec 2 9 x cosec 4 9 xdx = K cot 3 9 x + L tan 9 x + M cot 9 x + C, then find the values of K, L, and M. => K = - 2 9 , L = 1 9 , M = - 1 2 7 or K = - 1 9 , L = 2 9 , M = - 1 2 7 or K = - 1 27 , L = 1 9 , M = - 2 9 or K = - 1 9 , L = 1 2..

Find the derivative of e 9x cot 5 x with respect to x . => 5cosec 2 5 x ) or e 9 x (cot 5 x - cosec 2 5 x ) or e 9 x (9cot 5 x + 5cosec 2 5 x ) or e 9 x (9cot ..

Find the derivative of tan x . => - sec 2 x or - cos e c 2 x or sec 2 x or sec x cosec x..

d d x ( 7 x sin 2 x ) = => cosec 2 x (7 + x cot 2 x ) or cosec 2 x (7 - 14 x cot 2 x ) or - cosec 2 x (7 + 14..

If y = ln cot 5 x , then find d y d x . => ln(- 5cosec 2 5 x ) or tan 5 x or - 5cosec 5 x sec 5 x or 5cosec 5 x cot 5 x..