cosecant

f) cosec 180 o and cot 180 o are not defined. g) cosec 360 o and cot 360 o are not define..

Find f ′ ( p ), if f ( p ) = 8cot 7 p + 12 from the definition of derivative. => 1 56 sin 2 7 p or - 56 cosec 2 7 p or 56 cosec 2 7 p or - 7 cosec 2 7 p or - 8 cosec 2 7 p..

Find f ′( u ), if f ( u )= 2 u 2 + 4cot u 3 . => 4 u + 12 u 2 (cosec 2 u 3 ) or 12 u 2 (cosec 2 u 3 ) - 4 u or 4 u - (cosec 2 u 3 ) or 4 u - 12 u 2 (cosec 2 u 3 ) or 12 u 2 (cosec 2 u 3 )..

If y = 16cot (sec 3 x ), then find d y d x . => (cosec 2 (sec 3 x ))(sec 3 x tan 3 x ) or 48(cosec 2 (sec 3 x ))(sec 3 x tan 3 x ) or - 48(cosec 2 (sec 3 x ))(sec 3 x tan 3 x ) or does not exist..

i) The numerical values of sin q and cos q cannot be greater than 1. ii) The numerical values of sec q and cosec q can never be less than 1. iii) There is no restriction on the values of tan q and cot q since they can take any valu..

Find d d x ( cos 2 6 x + cot 2 8 x ) . => - 6 sin 12 x - 16 cot 8 x cosec 2 8 x or - 12 sin 12 x - 16 cot 8 x cosec 2 8 x or 6 sin 12 x + 16 cot 8 x cosec 2 8 x or 12 sin 12 x + 16 cot 8 x cosec 2 8 x..

If a non vertical line has an inclination θ with the positive x -axis, then find the slope m of the line in terms of θ. => cosec θ or cot θ or tan θ or sin θ..

d d x ( 7 x sin 2 x ) = => cosec 2 x (7 + x cot 2 x ) or cosec 2 x (7 - 14 x cot 2 x ) or - cosec 2 x (7 + 14 x cot 2 x ) or cosec 2 x (1 + 14 x cot 2 x )..

Find d d x ( cos 2 6 x + cot 2 8 x ) . => - 6 sin 12 x - 16 cot 8 x cosec 2 8 x or 6 sin 12 x + 16 cot 8 x cosec 2 8 x or - 12 sin 12 x - 16 cot 8 x cosec 2 8 x or 12 sin 12 x + 16 cot 8 x cosec 2 8 x..

Using quotient rule, we have = - cosec 2 x..