Derivative of Inverse Trignometric Functions
The Derivative of Inverse Trignometric Functions includes: 1. sin - 1 x, 2. cos - 1 x, 3. tan - 1 x, 4. cot - 1 x, 5. sec - 1 x, 6. cosec - 1 ..
If y = ln cot 5x , then find dydx.
If y = ln cot 5 x , then find d y d x . => ln(- 5cosec 2 5 x ) or tan 5 x or - 5cosec 5 x sec 5 x or 5cosec 5 x cot 5 x..
If f (w) = 3cot 4w5, then find Dw(f (w)).
If f ( w ) = 3cot 4 w 5 , then find D w ( f ( w ) ) . => - 3 cosec 2 (4 w 5 ) or - w 4 cosec 2 (4 w 5 ) or - 60 cosec 2 (4 w 5 ) or 60 w 4 cosec 2 (4 w 5 ) or - 60 w 4 cosec 2 (4 w 5 )..
Evaluate : ∫eloge42(cosec 4x)(cot 4x)dx
Evaluate : ∫ e log e 4 2 ( cos e c 4 x ) ( cot 4 x ) d x => cosec x + C or cosec 4 x + C or - 21 2 cosec 4 x + C or - 21 2 sec 4 x + C..
Signs of Trigonometric Ratios
i) The numerical values of sin q and cos q cannot be greater than 1. ii) The numerical values of sec q and cosec q can never be less than 1. iii) There is no restriction on the values of tan q and cot q since they can take any valu..
Find: ∫cos3 7xsin2 7xdx
Find: ∫ cos 3 7 x sin 2 7 x d x => 1 7 (- cosec 7 x - sin 7 x ) + C or 1 7 (cosec 7 x + sin 7 x ) + C or 1 7 ( - cosec 7 x + sin 7 x ) + C or 1 7 (cosec 7 x - sin 7 x ) + C..
Find the derivative of e9x cot 5x with respect to x.
Find the derivative of e 9x cot 5 x with respect to x . => 5cosec 2 5 x ) or e 9 x (cot 5 x - cosec 2 5 x ) or e 9 x (9cot 5 x + 5cosec 2 5 x ) or e 9 x (9cot 5 x - 5cosec 2 5 x )..
Evaluate: ∫cosec (8-5y)5 tan (8-5y)dy
Evaluate: ∫ cos e c ( 8 - 5 y ) 5 tan ( 8 - 5 y ) dy => - 1 5 cosec (8 - 5 y ) + C or 1 25 cosec (8 - 5 y ) + C or 1 75 cosec 3 (8 - 5 y ) + C or - 1 40 cosec (8 - 5 y ) + C or y 2 5 + C..
Find the derivative of f (x) = tanh- 1 (sin 4x).
Find the derivative of f ( x ) = tanh - 1 (sin 4 x ). => 4cosec 2 4 x or 4sec 4 x or - sec 4 x or sec 2 4 x or cosec 4 x..
Summary
sin A = cos (90 o - A) tan A . tan (90 o - A) = 1 sin 2 A + cos 2 A = 1 1 + tan 2 A = sec 2 A 1 + cot 2 A = cosec 2 ..
sin A = cos (90 o - A) tan A . tan (90 o - A) = 1 sin 2 A + cos 2 A = 1 1 + tan 2 A = sec 2 A 1 + cot 2 A = cosec 2 ..See what our Users say :
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