cosecant

1. sin A = cos (90 o - A). 2. sin A / cos a = tan A. 3. tan A x tan (90 o - A) = 1. 4. sin 2 A + cos 2 A = 1. 5. 1 + tan 2 A = sec 2 A. 6. 1 + cot 2 A = cosec 2 A. Where 'A' is the angl..

1. The reciprocal of cos q = 1/cos q = sec q . 2. The reciprocal of sin q = 1/sin q = cosec q . 3. The reciprocal of tan q = 1/tan q = cot q..

Find the derivative of cot x . => - cos e c 2 x or - sec 2 x or - sec x cosec x or - tan x..

Evaluate ∫ 4 9 cos 8 x 1 - cos 8 x d x . => - 49 8 cosec 8 x - 49 8 cot 8 x - 49 x + C or 1 8 cosec 8 x + 1 8 cot 8 x - x + C or - cosec 8 x - cot 8 x - x + C or 49cosec 8 x + 49cot 8 x + x + C..

Find the equation of the graph. => y = sec θ - 3 or y = cosec θ + 3 or y = sec θ + 3 or y = sec θ..

If f ( t ) = 9 sec 5 t , then find f ′ ( t ) using the definition of derivative. => 45 cosec 5 t tan 5 t or 45 sec 5 t cot 5 t or 45 sec 5 t tan 5 t or 45 tan 5 t or - 45 cosec 5 t cot 5 t..

∫ cos 3 8 x + cos 5 8 x sin 2 8 x + sin 4 8 x d x = => 1 8 (sin 8 x - 2cosec 8 x ) + C or 1 8 (sin 8 x - 2cosec 8 x - 6tan -1 (sin 8 x )) + C or (sin 8 ..

Find f ′( x ) for f ( x ) = 8 x 5 - 2log x + 3cot x . => 40 x 4 - 2 x - 3cosec 2 x or 40 x 4 or 40 x 4 - 3cosec 2 x or 40 x 4 - 2 x..

Evaluate : ∫ 1 1 + cos 2 x d x => - 2cosec 2 x + 2cot 2 x or - 2cot 2 x + 2cosec 2 x or cot 2 x 2 - cos e c 2 x 2 + C or - cot 2 x 2 + cos e c 2 x 2 + C..

Find the derivative of f ( x ) = e 4 x + cot 2 11 x . => 4 e 4 x + cot 11 x cosec 2 11 x or e 4 x - tan 11 x sec 2 11 x or 4 e 4 x + 22tan 11 x sec 2 11 x or 4 e 4 x - 22cot 11 x cosec 2 11 x..