cumulative frequency table standard deviation

Cumulative Frequency Distribution - Cumulative frequency is obtained by adding the frequency of a class interval and the frequencies of the preceding intervals upto that class interval. This is explained by an example below. The following ..

Standard Deviation - of a statistical data is defined as the positive square root of the arithmetic mean of the squared deviations of items from their arithmetic mean of the series under consideration. The standard deviation is denoted by s (sigma)...

The blood urea nitrogen (in milligrams per deciliter - mg/dl) count of 20 randomly selected patients is shown in the frequency distribution table. Blood urea nitrogen Frequency 11 - 13 3 13 - 15 4 15 - 17 3 17 - 19 5 19 - 21 5 Find the variance and standard h..

A field survey shows the lifetime (in years) of a particular model of a washing machine in the frequency distribution table. Lifetime of washing machines Number of washing machines 0 - 2 5 2 - 4 16 4 - 6 13 6 - 8 7 8 - 10 5 10 - 12 4 Find the variance and standard ..

The weight (in grams) of a sample of 50 eggs are as shown in the frequency distribution table. Weight Frequency 80 - 84 2 85 - 89 6 90 - 94 12 95 - 99 14 100 - 104 10 105 - 109 5 110 - 114 1 Find the variance and standard deviation. => 6.85 and 2.62..

80 randomly selected batteries were tested to determine their lifetime (in hours). The following frequency distribution was obtained. Lifetime of batteries Frequency 63.5 - 74.5 10 74.5 - 85.5 15 85.5 - 96.5 22 96.5 - 107.5 17 107.5 - 118.5 11 118.5 - 129.5 5 Find the variance a..

The rate of fuel consumption (in miles per gallon) of 30 selected sports utility vehicles are shown in the frequency distribution table. Fuel consumption Frequency 11.5 - 12.5 6 12.5 - 13.5 1 13.5 - 14.5 3 14.5 - 15.5 6 15.5 - 16.5 8 16.5 - 17.5 2 17.5 - 18.5 3 18.5 - ..

A survey conducted by an automobile company showed the number of cars per household and the corresponding probabilities. Number of cars X 1 2 3 4 Probability P(X) 0.32 0.51 0.12 0.05 Find the standard deviation. => 0.63 or 0.79 or 1.9 or 4.24..

The lengths (in miles) of 10 rivers taken randomly are shown here. Find the 98% confidence interval for the variance and standard deviation. Assume that the variable is normally distributed. 1928 1728 1234 1110 1000 2340 1995 2005 1947 1857 => 82215 < σ 2 < 853095 ; ..

The table represents the percentage of house owners and corresponding ages (in years) of a municipal area in the year 2000. Find the variance and standard deviation. Age Percentage of house owners 15-24 17.9 25-34 25.6 35-44 16.2 45-54 30.3 => 11.45 and 131.18 or 129.73 and..