differential equation numerical solution

01. An object of mass 5 kg is lifted up through a distance of 2 meter. What is the work done? Solution: W = F x s Also, force acting on the object is F = mg [Newton's second law of motion] Mass of the object (m) = 5 kg Distance moved = 2m Therefore, Work done = F x s 02. How ..

01. Calculate the kinetic energy of a body of mass 5 kg, which is moving with a velocity of 15m/s. Solution: Mass of the body (m) = 5kg Velocity of the body (v) = 15m/s Kinetic energy = 1/2mv 2 Kinetic energy = 562.5 J 02. A dog of mass 20kg is running at a constant speed of 12m/s..

01. A man of mass 60 kg runs up a flight of 60 steps in 40 seconds. If each step is 20 cm high, calculate his power. Solution : Since the man runs up a flight of steps, the work done will be equal to the potential energy. Height = height of one step x number of ste..

A solution obtained, by assigning particular values to the arbitrary constants in the general solution of the differential equation, is called its particular solution..

A functional relation between x and y which satisfies the given differential equation. Solution of a differential equation by the method of variables separable..

Aim - To extract a compound that is present in very small amounts in an aqueous solution with the help of an organic liquid in which that compound is highly solubl..

The slope field of a certain differential equation is shown. Which of the following is the solution to that differential equation? => y = e - x + C or y = ln x + C or y = - cos x + C or y = e x + C or y = sin x + C..

The slope field and graphical solution of a differential equation is shown. Which of the following is that differential equation? => d y d x = 1 x 2 + 1 or d y d x = x or d y d x = 1 x or d y d x = 1 x 2 or d y d x = x 2 + 1..

A current of 0.50 ampere is passing through a CuSO 4 solution. How many Cu + + ions will be deposited on cathode in 10 second..

(a) Here, n = 1+ 1 - 1 = 1 K p = K c (RT) 1 = K c RT (b) Here, n = 2- (3+1) = -2 K p = K c (RT) - 2 (c) Here, n = 2- (1+1) = 0 K p = K c (RT) 0 = K c (d) Here, n = 2+1-2 =1 K p = K c (RT) 1 = K c RT (d) Here, n = 2- (2+1)= -1 K p = K c (RT) - 1 = K c / RT 3. At 700 K, the equilibri..