diffusion equation numerical solution

It is a physical process that involves the movement of solute particles from the region of their higher concentration to the region of their lower concentration. Transport of materials within the cell is by diffusion. The entry of carbon dioxide into the stomata is by diffu..

Diffusion in Liquids - If a bottle of perfume is opened in one corner of a room, it spreads in the whole room by diffusion. If you drop a little ink in a beaker of water it will spread by itself in the beaker of water and the color spreads uniformly. Diffusion is the n..

01. Calculate the kinetic energy of a body of mass 5 kg, which is moving with a velocity of 15m/s. Solution: Mass of the body (m) = 5kg Velocity of the body (v) = 15m/s Kinetic energy = 1/2mv 2 Kinetic energy = 562.5 J 02. A dog of mass 20kg is running at a constant speed of 12m/s..

01. A man of mass 60 kg runs up a flight of 60 steps in 40 seconds. If each step is 20 cm high, calculate his power. Solution: Since the man runs up a flight of steps, the work done will be equal to the potential energy. Height = height of one step x number of ste..

Colloidal particles like solutes in true solution diffuse from a region of higher concentration to that of lower concentration. Because of their bigger sizes colloidal particles move slowly and diffuse at a slower rat..

If a bottle of perfume is opened in one corner of a room, it spreads in the whole room by diffusion. If you drop a little ink in a beaker of water it will spread by itself in the beaker of water and the color spreads uniformly. Diffusion is the natural process of intermingling..

It is a process, which involves movement of a substance from a region of its higher concentration to a region of its lower concentration. fig. 15.3 - Diffusion Molecules of any substance are in constant random movement in all fluids. This movement is called Brownian movement. Apart from t..

The molecules of the gas are in constant motion, at very high velocity. There is a great amount of intermolecular space between the molecules. When two gases are mixed, particles of one gas can easily pass through the intermolecular space of the other gas. As a result both the gases get completely..

Let the rate of diffusion of oxygen be r(O 2 ) = r 1 The rate of diffusion of the unknown gas r (x) = 4r Molecular mass of O, M(O) = 32 Molecular mass of unknown gas M (x) = M From Graham's Law of diffusion,..

(a) Here, n = 1+ 1 - 1 = 1 K p = K c (RT) 1 = K c RT (b) Here, n = 2- (3+1) = -2 K p = K c (RT) - 2 (c) Here, n = 2- (1+1) = 0 K p = K c (RT) 0 = K c (d) Here, n = 2+1-2 =1 K p = K c (RT) 1 = K c RT (d) Here, n = 2- (2+1)= -1 K p = K c (RT) - 1 = K c / RT 3. At 700 K, the equilibri..