distance learning institutions

Formerly called as National Botanical Garden, this institute is spread over an area of 75 acres. It has sections like orchid house, palms house, cactus house, portable garden, hydroponicium, vertical garden, a climber pergola and a medicinal plot. There is also a lake for aquatic plants...

The number of educational institutions in a city, in 1985, was 279 and in 1997, it became 371. Find the percent of increase in the number of educational institutions. => 42.97% or 37.97% or 330% or 32.97%..

Each room has 10 computers in a computer-learning institute. How many rooms are there in the institute if there are 70 computers all together? => 12 or 7 or 80 or 60..

The scatterplot shows the details of a survey by John on population of 10 cities and the number of educational institutes in these cities. => The correlation will not change. or The correlation will be weaker. or The correlation will be negative. or There will be no correlation...

The pie chart represents the different schools in the U.S. What fraction of the institutions are Colleges and Universities and Others? => 5 27 or 3 27 or 4 27 or 2 27..

Heights and Distances - One of the main use of trigonometry is to find the distances between points, or the heights of objects, without actually measuring these distances or these heigh..

Suppose a bus starting from a terminus A travels 15000 m to reach terminus B. Then the distance covered by the bus is 15000 m. Now if the bus returns to the terminus A, then what is the distance covered by the bus during the return trip? The distance covered is 1..

One of the main use of trigonometry is to find the distances between points, or the heights of objects, without actually measuring these distances or these height..

The distance between terminus A and terminus B is 150 km. A bus travels from terminus A to terminus B. The distance covered by the bus is 150 km. The bus travelling on the same route, returns from terminus B to the terminus A. Thus the total distance covered by the bus..

As proved earlier, the intensity of sound varies inversely as the square of the distance from the source. If two points are at distances d 1 and d 2 from a point source, then the intensities at these points will be in the inverse ratio of the squares of the distances..