Case - I
Let MM and MM' be two plane mirrors inclined at an angle 120 o and O be the object placed in between these mirrors. In this case there will be only two images viz., O 1 and O 2..
Let MM and MM' be two plane mirrors inclined at an angle 120 o and O be the object placed in between these mirrors. In this case there will be only two images viz., O 1 and O 2..Case 2
If the object is moving from -3 to -1,then displacement = x f - x i = -1 - (-3) = 2..
If the object is moving from -3 to -1,then displacement = x f - x i = -1 - (-3) = 2..Case 2
If the object is moving from -3 to -1 then displacement = x f - x i = -1 - (-3) = 2..
If the object is moving from -3 to -1 then displacement = x f - x i = -1 - (-3) = 2..Case 2:
When 'n' is a negative integer. Let n = -m and m > 0 ..
When 'n' is a negative integer. Let n = -m and m > 0 ..Case 2:
If the body is negatively charged, then the lines of force are directed towards the body. ..
If the body is negatively charged, then the lines of force are directed towards the body. ..Case III:
If D = 0 and all D 1 , D 2 and D 3 are zeros, this system has either infinite solution or no solution. In this case, put x = k(y = k or z = k), in any two of the equations, find y and z in terms of k. Substitute these values of x, y and z in terms of k, in the third..
Special cases
1) When both the cars are moving in the same direction, i.e., q = 0 0 degrees. Thus, the relative speed between two bodies moving in the same direction is equal to the difference of the individual speeds of two bodies. 2) When the two cars are moving along pa..
1) When both the cars are moving in the same direction, i.e., q = 0 0 degrees. Thus, the relative speed between two bodies moving in the same direction is equal to the difference of the individual speeds of two bodies. 2) When the two cars are moving along pa..Case 4:
When two sides b, c and an angle B opposite to one of the given sides are given. log sin C = log c + log B - log b which determines C. The equation (i) in general leads to two solutions say C 1 and C 2 (say such that C 1 + C 2 = 180), suppose C 1 is ..
When two sides b, c and an angle B opposite to one of the given sides are given. log sin C = log c + log B - log b which determines C. The equation (i) in general leads to two solutions say C 1 and C 2 (say such that C 1 + C 2 = 180), suppose C 1 is ..Case III
Let us now calculate the number of images formed if the two mirrors are placed parallel to each other i.e., the angle of inclination between them is 0 0..
Let us now calculate the number of images formed if the two mirrors are placed parallel to each other i.e., the angle of inclination between them is 0 0..Case (i)
C divides AB internally. Let A (x 1 , y 1 ) and B (x 2 , y 2 ) be the two points joined by line segment AB. Let C (x, y) be the point on the line segment such that (In this case, AC and CB are real in the same direction on the line AB.) Draw AP, CR and ..
C divides AB internally. Let A (x 1 , y 1 ) and B (x 2 , y 2 ) be the two points joined by line segment AB. Let C (x, y) be the point on the line segment such that (In this case, AC and CB are real in the same direction on the line AB.) Draw AP, CR and .. Result
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