Multiplication and division property
The following are also true. where a is a non-zero constant. ..
The following are also true. where a is a non-zero constant. ..Example:
Show that the function has a removal discontinuity at x = 4. Redefine the function f(x) at x = 4 to make it continuo..
Show that the function has a removal discontinuity at x = 4. Redefine the function f(x) at x = 4 to make it continuo..Example:
We write ..
We write ..Example:
Evaluate the limit..
Evaluate the limit..Example:
If Q(c) = 0, we can also factorise and cancel a common facto..
If Q(c) = 0, we can also factorise and cancel a common facto..Example:
At x =1, the numerator of the rational function 6, but denominator is 0. ..
At x =1, the numerator of the rational function 6, but denominator is 0. ..Example:
Find at least 3 sets of values for the variables satisfying the equation. 2x+y=5 Express y in terms of x. y=5-2x Select three values of x, find corresponding values of y. x=0, y=5-(2x0)=5 x=1, y=5-(2x1)=3 x=-1, y=5-(-2)=7 Draw the x and y - axes. Choose a suitable scale so as to locate the sel..
Find at least 3 sets of values for the variables satisfying the equation. 2x+y=5 Express y in terms of x. y=5-2x Select three values of x, find corresponding values of y. x=0, y=5-(2x0)=5 x=1, y=5-(2x1)=3 x=-1, y=5-(-2)=7 Draw the x and y - axes. Choose a suitable scale so as to locate the sel..Example:
x = 1, y = 1 is a solution of 2x + 3y = 5 2(1) + 3(1) = 5 x = -2, y = 3 is also a solution of 2x + 3y = 5 2(-2) + 3(3) = 5 -4 + 9 = 5 Similarly, we can find many more solutions for 2x + 3y ..
Example
x+2y+4..
Result
Pages   :     1     2     3     4     5     6     7     8     9     10     11
See what our Users say :
My daughter is getting 'A' grade in math, This is a great tutoring ...Thank you Tutor Vista..
I got a great help from tutors for my entrance test for math and English. Thank you so much
My grandson is getting a great math help from Tutor Vista, He is an A+ student in school now. Thank you so much!!!
Chemistry is a tough subject for me, I get a great help here along with a detailed explanation from a virtual tutor, it's really amazing - Nancy
Looking for More Help!
