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Choose the variable parts of the terms of the expansion.(c + d)5
Choose the variable parts of the terms of the expansion. ( c + d ) 5 => c 5 , d 5 or c 5 , c 4 d , c 3 d 2 , c 2 d 3 , c d 4 , d 5 or c 6 , d 6 or c 5 d 5 , c 4 d 4 , c 3 d 3 , c 2 d..
What is the number of terms in the binomial expansion of (x + y)8 ?
What is the number of terms in the binomial expansion of ( x + y ) 8 ? => 15 or 7 or 16 or 9..
Find the coefficient of the term x7 in the expansion of (x - 3)12.
Find the coefficient of the term x 7 in the expansion of ( x - 3) 12 . => - 192465 or - 192546 or - 192654 or - 192456..
Use binomial theorem to find the expansion of (2x + 3y) 3.
Use binomial theorem to find the expansion of (2 x + 3 y ) 3 . => 8x 3 + 36x 2 y + 54xy 2 + 27y 3 or x 3 + 18x 2 y + 18xy 2 + y 3 or 8x 3 + 36x 2 y + 36xy 2 + 27y 3 or 8x 3 + 27y 3..
Find the 16th term in the binomial expansion of (81 + x2 + 18x)8.
Find the 16 th term in the binomial expansion of (81 + x 2 + 18 x ) 8 . => 16 x 15 or - 16 x 15 or 15 x 16 or 16 x..
Find the sixth term in the binomial expansion (x - y4)10.
Find the sixth term in the binomial expansion ( x - y 4 ) 10 . => 252 x 5 y 5 or - 252 x 5 y 5 or 252 x 5 y 20 or - 252 x 5 y 20..
Find the value of x, if the 21st and 22nd terms which are in the expa..
Find the value of x , if the 21 st and 22 nd terms which are in the expansion of (1 + x ) 44 are equal. => 5 7 or 6 7 or 5 8 or 7 8..
Find the seventh term of the binomial expansion [x8 + y]16.
Find the seventh term of the binomial expansion [ x 8 + y ] 16 . => 16! 10! ( x 8 ) 1 0 or 16! (10! × 6!) ( x 8 ) 1 0 y 6 or 16! (10! × 6!) ( x 8 ) 1 6 y 7 or 16! 6! y 6..
A binomial expansion has 12 terms. The variable part of the first term..
A binomial expansion has 12 terms. The variable part of the first term is x 11 and the last term is y 44 . Find the variable parts of the second and third terms. => x 10 y 4 , x 9 y 8 or x 9 y 8 , x 11 y 44 or x 9 y 8 , x 10 y 4 or x 10 y 4 , x 11 y 44..
Find the expansion of the binomial function (a + b)5.
Find the expansion of the binomial function ( a + b ) 5 . => a 5 + 1 0 a 4 b + 1 0 a 3 + 5 a 2 or ( a+b )( a+b )( a+b )( a+b )( a+b ) or a 5 + b 5 or a 5 + 5 a 4 b + 1 0 a 3 b 2 + 1 0 a 2 b 3 + 5..
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